Jack ran 4 kilometers each day for 3 days. How many meters did jack run in 3 days?

Mathematics

2 answers:

Novosadov [1.4K]3 years ago

7 0

Answer:

12,000

Step-by-step explanation:

4 x 1000 x 3

mariarad [96]3 years ago

3 0

Answer:

12 kilometers= 12000 meters

Step-by-step explanation:

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A car has 15 gallons of gas in its tank. The car travels 35 miles per gallon of gas. It uses 1/35 of a gallon of gas to go one m

ikadub [295]

Answer:

2.86 gallons

Step-by-step explanation:

If 1/35 gallon of gas = 1 mile

To travel 100 miles,

1/35 × 100

= 0.0286 × 100

= 2.86 gallons

Therefore, the car needs 2.86 gallons of gas to travel 100 miles.

4 0

2 years ago

2. Solve the equation using the quadratic formula. -4x2 + 40x + 16 = 0 Page 1 of 2

kumpel [21]

The solution to given quadratic equation is x = -0.3851 or x = 10.3851

Solution:

Given equation is:

$-4x^2 + 40x + 16 = 0$

To find: solve by quadratic equation formula

$\text {For a quadratic equation } a x^{2}+b x+c=0, \text { where } a \neq 0\\\\x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Using the above formula,

$\text{ For} -4x^2 + 40x + 16 = 0 \text{ we have } a = -4 ; b = 40 ; c = 16$

Substituting the values of a = -4 ; b = 40 ; c = 16 in above quadratic formula we get,

$\begin{aligned}&x=\frac{-40 \pm \sqrt{40^{2}-4(-4)(16)}}{2 \times-4}\\\\&x=\frac{-40 \pm \sqrt{1600+256}}{-8}\\\\&x=\frac{-40 \pm 43.081}{-8}\\\\&x=\frac{-40+43.081}{-8} \text { or } x=\frac{-40-43.081}{-8}\\\\&x=-0.3851 \text { or } x=10.3851\end{aligned}$