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3 years ago

Solve the following equation. Then place the correct number in the box provided. Leave answer in terms of a mixed number.

Mathematics

2 answers:

Paha777 [63]3 years ago

5 0

<span>7x-2<10
7x<12
x=</span> $\frac{7}{12}$

Hope this helps!

Reika [66]3 years ago

3 0

Answer:

-2

Step-by-step explanation:

3 + x + 1 = 2

Okay so 3+1 =4.

To get something + 4 to equal 2 we need to use negatives.

-2. It is 2 spaces away from 0 and 4 spaces from 2.

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PLEASE HELP ILL GIVE BRAINLIEST!!

victus00 [196]

Answer:

73.12 cm

Step-by-step explanation:

The perimeter of the square is 3 sides of the square (the 4th side is not included because of the semicircle)

P square = 3 s

=3 (16)

=48 cm

The perimeter of the semicircle is 1/2 of the circumference of a circle

P semicircle = 1/2 (pi *d)

=1/2 (pi* 16)

= 8 pi

= 8 (3.14)

=25.12 cm

The total perimeter is the sum of the square and the circle

P total = P square + P semicircle

=48+25.12

=73.12 cm

8 0

4 years ago

Which products result in a difference of squares? Select three options. (x minus y)(y minus x) (6 minus y)(6 minus y) (3 + x z)(

ValentinkaMS [17]

Answer:

Third option: $(3 + xz)(-3 + xz)$

Fourth option: $(y^2 - xy)(y^2 + xy)$

Sixth option: $(64y^2 + x^2)(-x^2 + 64y^2)$

Step-by-step explanation:

By definition, we can factor the Difference between two squares:

$a^2 - b^2 = (a+b)(a-b)$

In order to find which products results in a difference of squares, we need to check each option:

$1.\ (x - y)(y - x)=(x)(y)+(x)(-x)-(y)(y)+(-y)(-x)=xy-x^2-y^2+xy=-x^2-y^2+2xy$

The product does not result in a difference of squares.

$2.\ (6 - y)(6 - y)$

Since the signs are equal ( $-$ ), the product will not result in a difference of squares.

Using Distributive Property for the other options, we get:

$3.\ (3 + xz)(-3 + xz)=(3)(-3)+(3)(xz)+(xz)(-3)+(xz)(xz)=\\\\=-9+3xz-3xz+x^2z^2=x^2z^2-9=(xz)^2-(3)^2$

The product results in a difference of squares.

$4.\ (y^2 - xy)(y^2 + xy)=(y^2)(y^2)+(y^2)(xy)-(xy)(y^2)-(xy)(xy)=\\\\=y^4+xy^3-xy^3-x^2y^2=y^4-x^2y^2=(y^2)^2-(xy)^2$

The product results in a difference of squares.

$5.\ (25x - 7y)(-7y + 25x)=(25x - 7y)(25x - 7y)$

Since the signs are equal ( $-$ ), the product will not result in a difference of squares.

$6.\ (64y^2 + x^2)(-x^2 + 64y^2)=(64y^2 + x^2)(64y^2 - x^2)=\\\\=(64y^2)(-x^2)+(64y^2)(64y^2)+(x^2)(-x^2)+(x^2)(64y^2)=\\\\=-64y^2x^2+4096y^4-x^4+64y^2x^2=\\\\=4096y^4-x^4=(64y^2)^2-(x^2)^2$

The product results in a difference of squares.

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