Question

In this diagram, ABAC – AEDF. If the

Answer 1

Answer:

Area of ∆EDF = 9.6 in.²

Step-by-step explanation:

Given:

∆BAC ~ ∆EDF

Area of ∆BAC = 15 in.²

EF = 4 in.

BC = 5 in.

Required:

Area of ∆EDF

SOLUTION:

The ratio of the area of two similar shape = the ratio of the square of their corresponding side lengths

Let x represent the area of ∆EDF

Therefore:

15/x = 5²/4²

15/x = 25/16

Cross multiply

x×25 = 15×16

25x = 240

Divide both sides by 25

x = 240/25

x = 9.6

Area of ∆EDF = 9.6 in.²