Answer:
FALSE
Step-by-step explanation:
<E in ∆AED ≅ <E in ∆CEB.
Both are 90°.
Side ED ≅ Side EB
Side AD ≅ Side CB.
Thus, two sides (ED and AD) and a non-included angle (<E) of ∆AED are congruent to corresponding two sides (EB and CB) and a non-included angle (<E) of ∆CEB. Therefore, by A-S-S Congruence Theorem, both triangles are congruent to each other not by SSS.
Counting by Tens with numbers
10, 20, 30, 40, 50, 60, 70, 80, 90
Counting by Tens with words
ten, twenty, thirty, forty, fifty, sixty, seventy, eighty, ninety, one hundred
Number Patterns when counting by Tens
When you count by tens the numbers create a pattern. All the numbers end with a zero. The first digits are just like the numbers when you count (1, 2, 3, 4, 5, etc.). This pattern gives the numbers 10, 20, 30, 40, 50, etc.
found from: http://www.aaamath.com/k4c_cox1.htm
So first you would need to time 5 and 4.33 then divide by 2 then times by 3 cause there are 3 triangles. it would equal C.
*12 + 1.5x = 16 + 0.50x*
That's the answer, since I'm late.
This is correct because when setting up this sentence as an equation, you need to look at the numbers and how they're used. There are independents and dependents.
indep.:
12,16
dep.:
1.50,0.50
Furthermore, there are 1 of each on both sides of the equation, match them from the equation by name and you get the answer.
There are 26 letters of the alphabet
you want 6-character passwords without repetitionthe first time you pick a letter, you pick from 26 lettersthe second time you pick a letter, you pick from 25 letters (no repetitions !)the third time you pick a letter, you pick from 24 letters, and so onthe answer is 26*25*24*23*22*21=165,765,600 passwords
