Answer:
<h2>Option A = 1*3 = 3 unit² </h2>F = (3,7)
G = (6,4)
H = (5,3)
E= (2,6)
= (3 units)
<h3>Distance between FE = GH </h3>= 1 units
Area = 3* 1
= 3 units²
Points A and B have opposite x-coordinates but the same y-coordinates.
1 answer:
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The diet will include <u>123.75 </u>daily grams of protein
<h3>Further explanation</h3>One variable linear equation is an equation that has a variable and the exponent number is one.
Can be stated in the form:
or
ax + b = c, where a, b, and c are constants, x is a variable
We complete the task :
A nutritionist planning a diet for a football player wants him to consume 3,500 Calories and 725 grams of food daily. Calories from fat and protein will be 45% of the total Calories. There are 4, 4, and 9 Calories per gram for protein, carbohydrates, and fat, respectively. How many daily grams of protein will the diet include?
- 243.75
- 481.25
- 123.75
- 120
Calories from fat and protein will be 45% (0.45) of the total Calories
Calories from fat and protein = 0.45 x 3500 = 1575 calories
Calories from carbohydrates = 3500 - 1575 = 1925 calories
So mass for carbohydrates = 1925 : 4(4 calories/gram) = 481.25 grams
Then mass for fat and protein = 725 - 481.25 = 243.75 grams
We can make equation for fat and protein
1. 4 calories. mass of protein(p) + 9 calories . mass of fat(f) = 1575 calories
2. mass of protein(p) + mass of fat(f) = 243.75
we can simplify :
1. 4p+9f = 1575
2. p + f = 243.75 ⇒ f = 243.75 - p
we substitute equation 2 into equation 1 :
4p + 9(243.75-p) = 1575
4p + 2193.75-9p=1575
-5p = -618.75
p = 123.75
<h3>Learn more</h3>
linear equation
Keywords : one variable, linear equation ,diet, nutritionist,calories, fat, proteins, carbohydrates, daily grams
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