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Yakvenalex [24]
2 years ago
10

Margo is picking up 600 -ohm resistors for a physics project . (Ohms are the units used to measure circuit resistance.) The pack

age guarantees that the actual resistance is within 10% of the package rating. Which of the following inequalities best models the range of resistances, r?

Mathematics
1 answer:
laila [671]2 years ago
7 0

Answer:

B

Step-by-step explanation:

Resistance tolerance (like 10%) means that the value is 10% either side of the color coded value.

10% of 600 = 10/100 * 600 = 60

So the highest value can be 600 + 60 or 660

The lowest value is 600 - 60 = 540

The answer is

540 <= r <= 660

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gayaneshka [121]
Got it :)Thank you!!!!!!!
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2 years ago
PLEASE HELP ME ASAPPPP
frutty [35]

Answer:

The answer is

90 degrees the first one is I don't know about the rest sorry

Step-by-step explanation:

7 0
2 years ago
What is the value of x if...<br> 9x - 4 - 4x = 8 + 3x
Ierofanga [76]

Hello!

Answer:

x=6

Step-by-step explanation:

Hope this helps!

7 0
2 years ago
Silvia has completed 8 math exercises e. This one fourth of the assignment. How many exercises were assigned?
babymother [125]

Answer:

32

Step-by-step explanation:

since there are 4 parts, multiply 8 by 4

7 0
3 years ago
A ladder 10 m long,leans against a vertical wall at an angle of 70° to the ground.if the ladder slips down the wall 4m,find,corr
lina2011 [118]

Answer:

(a) the new angle the ladder makes with the ground is 32.7^o

(b) the ladder slipped back about 5 meters

Step-by-step explanation:

Notice that the ladder doesn't change its length in the process.

So let's start from the initial situation , finding the distance from the ground at which the ladder touches the wall when the angle with the ground is 70^o. Notice that this situation is represented by a right angle triangle with the right angle between the wall and the ground (see attached image), and that we can use the sine function to find the side opposite to the 70 degree angle:

sin(70^o)=\frac{opposite}{hypotenuse} \\sin(70^o)=\frac{h}{10}\\h=10\, sin(70^o) \approx 9.4 \,\,m

therefore 9.4 meters is approximately the height at which the ladder touches the wall initially.

Now, if the tip of the ladder goes down the wall 4 meters, it is now at 9.4 m - 4 m = 5.4 m from the ground. We can therefore use again the sine function to solve for the new angle:

sin(x)=\frac{opposite}{hypotenuse} \\sin(x)=\frac{5.4}{10} \\sin(x)=0.54\\x=arcsin(0.54)\\x= 32.7^o

To answer the second question we need to find the original distance from the wall that the bottom of the ladder was originally, and for that we can use the cosine function:

cos(70^o)=\frac{adjacent}{hypotenuse} \\cos(70^o)=\frac{x}{10}\\x=10\,cos(70^o)\\x\approx 3.4  \,\,m

Now fro the new position of the bottom of the ladder relative to the wall:

cos(32.7^o)=\frac{adjacent}{10} \\adjacent=10\,cos(32.7^o)\\adjacent\approx 8.4\,\,m

then the difference in between those two distances is what we need:

8.4 m - 3.4 m = 5 m

4 0
3 years ago
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