This must be on the moon as the acceleration due to gravity in this equation must be around 1/8 that on earth. :) Anyway...
h=-2t^2+9t+11
A)
dh/dt=-4t+9, when velocity, dh/dt=0, it is the maximum height reached
dh/dt=0 only when 4t=9, t=2.25 seconds
h(2.25)=21.125 ft (21 1/8 ft)
B)
As seen in A), the time of maximum height was 2.25 seconds after the squirrel jumped.
C)
The squirrel reaches the ground when h=0...
0=-2t^2+9t+11
-2t^2-2t+11t+11=0
-2t(t+1)+11(t+1)=0
(-2t+11)(t+1)=0, since t>0 for this problem...
-2t+11=0
-2t=-11
t=5.5 seconds.
(3x-9) +(x+19)+x=180
5x+10=180
-10=-10
5x=170
5 = 5
x=34
2x+(2x+10)+x=180
5x+10=180
-10=-10
5x=170
5 = 5
x=34
yes they are similar
9514 1404 393
Answer:
B. Two
Step-by-step explanation:
There are two points that are 4 inches from A and 6 inches from B.
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<em>Additional comment</em>
They are at the intersection points of circle A with radius 4 inches and circle B with radius 6 inches.
Answer:
x = 28
m∠ACD = 68°
Step-by-step explanation:
∠BAE ≅∠DAC because they are vertical angles
∠ACD = 180 - 124 = 56°
to find 'x': 56 + 2x + (180 - 4x) = 180
236 - 2x = 180
-2x = -56
x = 28
m∠ACD = 180 - 4(28) = 180 - 112 = 68°
