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Wittaler [7]
3 years ago
14

A cylinder has a diameter of 20cm.

Mathematics
1 answer:
Vladimir [108]3 years ago
5 0

Answer:

V = 1200π

Step-by-step explanation:

Volume of a cylinder formula:

  • V = πr²h

Let's find the height of the cylinder by multiplying 20 cm by 3/5.

  • 20 * 3/5 = 60/5 = 12 cm

The radius is 1/2 of the diameter, so:

  • 20 * 1/2 = 20/2 = 10 cm

Substitute 12 for h and 10 for r into the volume formula.

  • V = π(10)²(12)

Simplify.

  • V = π * 100(12)  
  • V = π * 1200

The volume of a cylinder, in terms of π, is V = 1200π.

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Which inequality is equivalent to x-6/x+5≥x+7/x+3?
yawa3891 [41]
To find equivalent inequalities you have to work the inequality given.

The first step is transpose on of sides to have an expression in one side and zero in the other side:

  x - 6        x + 7
--------- ≥  --------
  x + 5       x + 3

=>

  x - 6          x + 7
--------- -  --------   ≥ 0
  x + 5       x + 3

=>

 (x - 6) (x + 3) - (x + 7) (x + 5)
--------------------------------------- ≥ 0
          (x + 5) (x + 3)

=>

 x^2 - 3x - 18 - x^2 - 12x - 35
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That is an equivalent inequality. Sure you can arrange it to find many other equivalent inequalities. That is why you should include the list of choices. Anyway from this point it should be pretty straigth to arrange the terms until making the equivalent as per the options.
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Westkost [7]

Answer:

1.333 repeated

Step-by-step explanation:

8 0
2 years ago
I NEED HELP PLEASE, THANKS! :)
marissa [1.9K]

Answer:

x = 28.01t,

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Step-by-step explanation:

If we are given that an object is thrown with an initial velocity of say, v1 m / s at a height of h meters, at an angle of theta ( θ ), these parametric equations would be in the following format -

x = ( 30 cos 20° )( time ),

y = - 4.9t^2 + ( 30 cos 20° )( time ) + 2

To determine " ( 30 cos 20° )( time ) " you would do the following calculations -

( x = 30 * 0.93... = ( About ) 28.01t

This represents our horizontal distance, respectively the vertical distance should be the following -

y = 30 * 0.34 - 4.9t^2,

( y = ( About ) 10.26t - 4.9t^2 + 2

In other words, our solution should be,

x = 28.01t,

y = 10.26t - 4.9t^2 + 2

<u><em>These are are parametric equations</em></u>

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