Answer:
since -3.73 is less than 1.645, we reject H₀.
Therefore this indicate that the proposed warranty should be modified
Step-by-step explanation:
Given that the data in the question;
p" = 13/20 = 0.65
Now the test hypothesis;
H₀ : p = 0.9
Hₐ : p < 0.9
Now lets determine the test statistic;
Z = (p" - p ) / √[p×(1-p)/n]
= (0.65 - 0.9) /√[0.9 × (1 - 0.9) / 20]
= -0.25 / √[0.9 × 0.1 / 20 ]
= -0.25 / √0.0045
= -0.25 / 0.067
= - 3.73
Now given that a = 0.05,
the critical value is Z(0.05) = 1.645 (form standard normal table)
Now since -3.73 is less than 1.645, we reject H₀.
Therefore this indicate that the proposed warranty should be modified
Answer:
Step-by-step explanation:
distance flown in 5.4 hours = 245.6 miles
distance flown in 1 hour = 245.6/5.4
= 45.481 miles
Hope this helps
plz mark as brainliest!!!!!
Answer:
No
Step-by-step explanation:
25-18 = 7 w
45-36=9 <em>l</em>
<em>They don't match up ^</em>
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Answer:
5. (3)
6. (1)
Step-by-step explanation:
Answer:
Option D. (x + 4)(x + 1)
Step-by-step explanation:
From the question given above, the following data were obtained:
C = (6x + 2) L
D = (3x² + 6x + 9) L
Also, we were told that half of container C is full and one third of container D is full. Thus the volume of liquid in each container can be obtained as follow:
Volume in C = ½C
Volume in C = ½(6x + 2)
Volume in C = (3x + 1) L
Volume in D = ⅓D
Volume in D = ⅓(3x² + 6x + 9)
Volume in D = (x² + 2x + 3) L
Finally, we shall determine the total volume of liquid in the two containers. This can be obtained as follow:
Volume in C = (3x + 1) L
Volume in D = (x² + 2x + 3) L
Total volume =?
Total volume = Volume in C + Volume in D
Total volume = (3x + 1) + (x² + 2x + 3)
= 3x + 1 + x² + 2x + 3
= x² + 5x + 4
Factorise
x² + 5x + 4
x² + x + 4x + 4
x(x + 1) + 4(x + 1)
(x + 4)(x + 1)
Thus, the total volume of liquid in the two containers is (x + 4)(x + 1) L.
