C- Often times, if someone is using a coupon, they just want the lowest price and don't care what toothpaste is considered "the Best."
Answer:
y=5/6x+8
Step-by-step explanation
This is definitely parallel
Answer:
y= 3/5x+ 6.2
Step-by-step explanation:
the slope is change in y over change in x.
-4-(-1) divided by 3-8 will be -3/-5 = 3/5
For the y-intercept, plug in x and y values. I will use (3,8).
8= 3/5(3)+b
8= 9/5+b
(subtract 9/5 from both sides)= 6 and 1/5 or 6.2 as a decimal.
Answer: 6 years old.
Step-by-step explanation:
For this exercise let "x" represents your present age.
According to the information provided in the exercise, you know that In three years, Chad will be three times your present age.
Then, your age in three years can be represented with the following expression:

Knowing at that time Chad's age will be three times yours and you will be half as old as old as Chad, you can write the following equation to represent this situation:

Therefore, the final step is to solve for "x" in order to find its value.
You get that this is:

The marginal distribution for gender tells you the probability that a randomly selected person taken from this sample is either male or female, regardless of their blood type.
In this case, we have total sample size of 714 people. Of these, 379 are male and 335 are female. Then the marginal probability mass function would be
![\mathrm{Pr}[G = g] = \begin{cases} \dfrac{379}{714} \approx 0.5308 & \text{if }g = \text{male} \\\\ \dfrac{335}{714} \approx 0.4692 & \text{if } g = \text{female} \\\\ 0 & \text{otherwise} \end{cases}](https://tex.z-dn.net/?f=%5Cmathrm%7BPr%7D%5BG%20%3D%20g%5D%20%3D%20%5Cbegin%7Bcases%7D%20%5Cdfrac%7B379%7D%7B714%7D%20%5Capprox%200.5308%20%26%20%5Ctext%7Bif%20%7Dg%20%3D%20%5Ctext%7Bmale%7D%20%5C%5C%5C%5C%20%5Cdfrac%7B335%7D%7B714%7D%20%5Capprox%200.4692%20%26%20%5Ctext%7Bif%20%7D%20g%20%3D%20%5Ctext%7Bfemale%7D%20%5C%5C%5C%5C%200%20%26%20%5Ctext%7Botherwise%7D%20%5Cend%7Bcases%7D)
where G is a random variable taking on one of two values (male or female).