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mario62 [17]
3 years ago
9

Find the center and radius of the circle having the equation: x2 - 10x + y2 - 2y + 15 = 0

Mathematics
1 answer:
Goshia [24]3 years ago
4 0

Answer:

Step-by-step explanation:

hello :

(x² - 10x) + (y² - 2y) + 15 = 0

(x² - 10x+25-25) + (y² - 2y+1-1) + 15 = 0

(x² - 10x+25)-25 + (y² - 2y+1)-1 + 15 = 0

(x-5)²+(y-1)² = 11

the center is (5;1) and radius √11

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What is the solution to the equation 13.7y = 6.2y + 30?
il63 [147K]

Here, we are required to determine the solution to the equation: 13.7y = 6.2y + 30?

The solution to the equation is y = 7.5

The solution is thus,

  • 13.7y = 6.2y + 30
  • 13.7y - 6.2y = 30
  • 7.5y = 30

Therefore, y = 30/7.5 = 4

Therefore, y = 4 is the solution to the equation.

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brainly.com/question/12184348

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2 years ago
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solniwko [45]

Answer:

r = 8

Step-by-step explanation:

6r = 95-47

6r = 48

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2 years ago
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Nady [450]

OPTION D = 2q is right answer

6 0
3 years ago
Which number is three hundred thousand times larger than 1.6 x 102 ? A) 4.8 x 106 B) 4.8 x 107 C) 4.8 x 108 D) 4.8 x 109
Bas_tet [7]
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8 0
3 years ago
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{20,1,6,10,11}<br> Find the subset and the proper subset.
liubo4ka [24]
With 5 elements in A={20,1,6,10,11}, there are 2^5=32 possible subsets, including
the null set, and A itself.
Any subset that is identical to A is NOT a proper subset.
Therefore there are 31 proper subsets, plus the subset {20,1,6,10,11}.

The subsets are:
null set  {} (has no elements) ........total 1
{20},{1},{6},{10},{11}.......................total 5
{20,1},{20,6}...{10,11}.....................total 10
{20,1,6},{20,1,10},...{6,10,11}.........total 10
{20,1,6,10}...{1,6,10,11}.................total 5
{20,1,6,10,11}.................................total 1
Altogether 32 subsets.


4 0
3 years ago
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