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Over [174]
3 years ago
6

I need help with all of them

Mathematics
1 answer:
Softa [21]3 years ago
3 0

Answer:

Part A: Triangles QPR and QPS are similar.

Part B: They are similar because if you rotate QPS to line up the right angles, then QPS would be a smaller version of QPR.

*not sure how to do part c*

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The following data is from a simple random sample of 12 students GPAs. 3.12 2.45 4.0 3.76 3.54 2.78 3.39 3.21 1.98 3.43 3.98 2.7
Rufina [12.5K]

Answer: 3. 2

Step-by-step explanation:

Given the data:

3.12 2.45 4.0 3.76 3.54 2.78 3.39 3.21 1.98 3.43 3.98 2.77

Point estimate of population mean :

Σx / N

(3.12 + 2.45 + 4.0 + 3.76+ 3.54 + 2.78 + 3.39 + 3.21 + 1.98 + 3.43 + 3.98 + 2.77)

= 38.41 / 12

= 3.2008

4 0
3 years ago
A cone is sliced such that the cross section is perpendicular to its base and the cross section intersects its vertex. What is t
Rashid [163]

Circle, A cone is made of circles that get smaller


5 0
4 years ago
Read 2 more answers
Name three solutions of x > 10.5
Svetllana [295]
In the problem is says that d is greater than 10.5 so any value greater than 10.5 is the answer

X = 11
X= 12
X= 14.
5 0
3 years ago
the line below contains X,Y,and Z, in that order. The ratio of the length of XY to the length of YZ is 5:9. If it can be determi
maw [93]

Answer:

\dfrac{XY}{XZ} =\dfrac{5}{14}

Step-by-step explanation:

We are give the following in the question:

\dfrac{XY}{YZ} = \dfrac{5}{9}

We have to find the ration of the length of XY to the length XZ.

This, can be done as:

\dfrac{XY}{XZ} = \dfrac{XY}{XY+YZ}\\\\\Rightarrow \dfrac{XZ}{XY} = \dfrac{XY+YZ}{XY}  = 1 + \dfrac{YZ}{XY}\\\\\Rightarrow \dfrac{XZ}{XY} = 1+\dfrac{9}{5} = \dfrac{14}{5}\\\\\Rightarrow \dfrac{XY}{XZ} =\dfrac{5}{14}

Thus, the ration XY:XZ is 5:14

8 0
3 years ago
A DNA sequence can be represented as a string of the letters ACTG (short for adenine, cytosine, guanine, and thymine). How many
maria [59]

To solve that question we can think by the following way:

  • The first letter can be any of the letters (A, C, T or G). Therefore there are 4 possibilites.
  • To choose the second letter of the sequence, any letter also can be chose. So, one more time, there are 4 possibilites.

Using the fundamental principle of counting, we will find out that can be formed 4\times 4 = 16 differents sequences (for example, AA, AG, TT, TG, CT...).

Know we know that, we can generalize. If I have n elements and I must choose one of them t times to do a sequence, the total number of sequence that I can form will be n^t.

In our question, we want to know how many DNA sequence are exactly 29 letters long. As indicated above, the answer for that is 4\times 4\times 4\times ... \times 4 (29 times) = 4^{29}.

Therefore, there are 4^{29} DNA sequences with exactly 29 letters long.

I hope I've helped you. =D

Enjoy your studies. \o/

8 0
3 years ago
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