All categories

3 years ago

Can somebody please write it down like show the work I need to know thanks

Mathematics

1 answer:

Nataly [62]3 years ago

5 0

Answer:

-5/33

Step-by-step explanation:

You might be interested in

which set of steps shows the solution to the equation 2y = −8? y = −8 − 2; y = 6 y = −8 ÷ (−2); y = 4 y = −8 ÷ 2; y = −4 y = −8

xz_007 [3.2K]

Answer: The correct option is

(C) y = −8 ÷ 2; y = −4.

Step-by-step explanation: We are given to select the correct steps that shows the solution to the following equation :

$2y=-8~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

We know that

the solution to the equation $ax=b,~~\textup{a,b are real numbers}$ is given by

$ax=b\\\\\Rightarrow x=b\div a.$

Therefore, the solution of equation (i) is as follows :

$2y=-8\\\\\Rightarrow y=-8\div 2\\\\\Rightarrow y=\dfrac{-8}{2}\\\\\Rightarrow y=-4.$

Thus, (C) is the correct option.

6 0

3 years ago

Find the total surface area of this triangular prism. 10 cm 6 cm 4 cm 8 cm

timama [110]

Answer:

144

Step-by-step explanation

8x6=48

48 divided by 2=24

24x2=48

4x10=40

8x4=32

4x6=24

add them all together so 48+40+32+24=144

7 0

2 years ago

Write the equation in point-slope form of the line that passes through the given point and has the given slope (4,-7); m= -1/4

kicyunya [14]

Answer:

y + 7 = -1/4(x - 4)

General Formulas and Concepts:

Algebra I

Point-Slope Form: y - y₁ = m(x - x₁)

x₁ - x coordinate
y₁ - y coordinate
m - slope

Step-by-step explanation:

Step 1: Define

Slope m = -1/4

Point (4, -7)

Step 2: Write Function

y + 7 = -1/4(x - 4)

6 0

3 years ago

Plz help me !!!!!!!!

vazorg [7]

You factor the numerator and denominator and cancel the common factors. So maybe that should help you

8 0

3 years ago

Read 2 more answers

Please help and thank you

tatiyna

Answer:

$b_{1}=\frac{2A}{h}-b_{2}$

Step-by-step explanation:

Given: $A=\frac{1}{2}(b_{1} +b_{2})h$

We need to completely isolate $b_{1}$ to solve.

$A=\frac{1}{2}(b_{1} +b_{2})h$

$A=(\frac{1}{2}b_{1} +\frac{1}{2} b_{2})h$

$A=\frac{1}{2}b_{1} h+\frac{1}{2}b_{2}h$

$-\frac{1}{2}b_{1}h+A=\frac{1}{2}b_{2}h$

$-\frac{1}{2}b_{1}h=-A+\frac{1}{2}b_{2}h$

$-\frac{1}{2}b_{1}=\frac{-A}{h}+\frac{1}{2}b_{2}$

Finally, multiply both sides by -2 to completely isolate $b_{1}$ .

$b_{1}=\frac{2A}{h}-b_{2}$

5 0

3 years ago

Read 2 more answers