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Radda [10]
3 years ago
10

HELPPPP

Mathematics
1 answer:
vichka [17]3 years ago
3 0

Answer:

Step-by-step explanation:

15.5cm(40mi/2.5cm)=620mi/2.5

248mi

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Sonya and her family went to dinner. The cost of the meal was $47.28. They left a 15% tip. What was the total amount sonyas fami
chubhunter [2.5K]

Answer:

$54.37

Step-by-step explanation:

First, need to find 15% of 47.28.

47.28 x .15 = 7.092

Then we add that to the original cost.

47.28+7.092 = 54.372

Round your answer

$54.37

Hope this helped!

3 0
3 years ago
Kallisto built a rectangular sign that measured 2 and 3/4. The width is 1 and 1/4 shorter than the length. To find the area, mul
prisoha [69]

Answer:

<em>l</em> = 1 5/16

w = 1/16

A = 21/16 x 1/16 = 21/256

Step-by-step explanation:

Perimeter = 11/4

<em>l</em> = length

w = <em>l</em> - 5/4

2<em>l</em> + 2(<em>l</em> - 5/4) = 11/4

2<em>l</em> + 2<em>l</em> - -5/2 = 1/4

multiply each side by 4

8<em>l</em> + 8<em>l </em>- 10 = 11<em> </em>

16<em>l</em> = 21

<em>l</em> = 21/16 or 1 5/16

width = 21/16 - 20/16 = 1/16

8 0
3 years ago
Determine the perimeter
nordsb [41]

Answer:

139

Step-by-step explanation:

14+14+28+33+33+17 = 139

6 0
3 years ago
Read 2 more answers
Find the area of each shaded sector. Round to the hundredths place.
kati45 [8]

Answer:

200

Step-by-step explanation:vbc i know

3 0
3 years ago
Find a polynomial function of least degree having only real coefficients, a leading coefficient of 1, and roots of 2-√6 , 2+ √6
horsena [70]

Answer:

x^{4} -18x^{3}+104x^{2} -172x-100

Step-by-step explanation:

The 3 roots are given out of which 2 are real and 1 is imaginary. For a polynomial of least degree having real coefficients, it must have a complex conjugate root as the 4th root. Therefore, based on 4 roots, the least degree of polynomial will be 4. Finding the polynomial having leading coefficient=1 and solving it based on multiplication of 2 quadratic polynomials, we get:  

\\\\x_{1} = 2-\sqrt{6} \\x_{2} = 2+\sqrt{6} \\x_{3}=7-i \\x_{4}=7+i \\\\P(x)=1(x-x_{1})(x-x_{2} )(x-x_{3} )(x-x_{4} ) \\\\=(x-(2-\sqrt{6}))(  x-(2+\sqrt{6} )) (x-(7-i))( x-(7+i))\\=((x-2)+\sqrt{6})( ( x-2)-\sqrt{6} ) ((x-7)+i)( (x-7)-i)\\=((x-2)^{2} -(\sqrt{6} )^{2} )((x-7)^{2}-(i)^{2})\\=(x^{2} -4x-2)(x^{2} -14x+50)\\=x^{4} -18x^{3}+104x^{2} -172x-100\\

7 0
3 years ago
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