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bogdanovich [222]
3 years ago
8

Numbers 37 and 39. I’m not sure how to solve them

Mathematics
1 answer:
Marrrta [24]3 years ago
8 0
37. 3/8 hours

You can get this by dividing 3/4 by 2. 

The key to doing these types of problems is remembering that if they are going faster by that much, it doesn't matter what the speeds are. You can treat it as if one is standing still and the other is going 2mph. 
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HELP PLS!! ILL GIVE POINTS !! :(( m
vesna_86 [32]

Answer:  Choice D

15(cos85° + i sin85°)

===========================================================

Explanation:

Let's say we had these two general complex numbers, which are in polar form.

z_1 = r_1*\left(\cos(\theta_1)+i*\sin(\theta_1)\right)\\\\z_2 = r_2*\left(\cos(\theta_2)+i*\sin(\theta_2)\right)\\\\

We can abbreviate them into the shorthand form

z_1 = r_1*\text{cis}(\theta_1)\\\\z_2 = r_2*\text{cis}(\theta_2)\\\\

The notation "cis" stands for "cosine i sine".

Now that we have those complex numbers set up, multiplying them is as simple as saying this:

z_1*z_2 = (r_1*r_2)*\text{cis}(\theta_1+\theta_2)

We do two basic things:

  1. Multiply the r values out front
  2. Add the theta values inside the the cis function

---------------------------------------

With all that in mind, let's tackle the problem your teacher gave you.

The given complex numbers

z_1 = 5*\left(\cos(15^{\circ})+i*\sin(15^{\circ})\right)\\\\z_2 = 3*\left(\cos(70^{\circ})+i*\sin(70^{\circ})\right)\\\\

abbreviate into

z_1 = 5*\text{cis}(15^{\circ})\\\\z_2 = 3*\text{cis}(70^{\circ})\\\\

then those multiply to

z_1*z_2 = (r_1*r_2)*\text{cis}(\theta_1+\theta_2)\\\\z_1*z_2 = (5*3)*\text{cis}(15+70)\\\\z_1*z_2 = 15\text{cis}(85^{\circ})\\\\z_1*z_2 = 15\left(\cos(85^{\circ})+i\sin(85^{\circ})\right)\\\\

which is why choice D is the final answer.

7 0
4 years ago
What is the area of the polygon below ?
elena55 [62]

It's best to think of oddly shaped polygons as different simple shapes within itself. You can divide them into two rectangles, solve for their areas separately, then add them together. (Halves slip horizontally)

6*11 would be the top half, which equals 66 square units

It is not given the amount of units long the longest side is, but you can figure it out by adding the sides given above. (7, 11, and 6)

5*24 would be the bottom half; 120 square units

Add both areas together to get the overall area of the polygon given

66+120=186

4 0
3 years ago
Can someone help me on this pls i will give brainliest
Dmitrij [34]
His error is in step 3. The variable x is being multiplied by -7 and therefore he should have divided both sides by -7, not 7 as he did.
8 0
3 years ago
Read 2 more answers
Use the method that you described in item 4 to answer the following
Kruka [31]

Answer:

Step-by-step explanation:

3 0
4 years ago
Helpppp me plz i need help i need help
Anni [7]

Answer: \frac{1}{8}

Step-by-step explanation:

- A coin has 2 sides. Which means the probability of the coin landing on one side will be \frac{1}{2}.

- Since there are three coins, we multiply \frac{1}{2} three times ( \frac{1}{2}* \frac{1}{2}* \frac{1}{2}) to get the answer of \frac{1}{8}

5 0
3 years ago
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