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2 years ago

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a piece of gum is stuck to the tire of a bike wheel in motion. The vertical distance between the gum and the ground, in centimet

ers, is modeled by H(t) where t is the time in seconds. The function is graphed below along with one segment highlighted

1 answer:

melamori03 [73]2 years ago

8 0

Answer:

im not too sure but i got the exact same answers witten down i j have to find it

Step-by-step explanation:

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The first jumbo jet was the Boeing 747, which is 70.5 meters long. The wingspan of a 747 is 60 meters. A model 747 has a wingspa

nydimaria [60]

Answer:

94 cm

Step-by-step explanation:

Set up and solve an equation of ratios:

wingspan length

60 meters 70.5 m

----------------- = ----------------

80 cm x

Cross multiplying:

(60 m)x = (70.5 m)(80 cm)

Solve for x by dividing both sides of this equation by 60 m:

x = (70.5 m)(80 cm) / (60 m) = 94 cm

The length of the model should be 94 cm.

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3 years ago

This means we increase the x value by 1.

velikii [3]

Answer:

The answer is option C, that is, (2,6)

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3 years ago

n a survey, 480 people, or 75%, said they attended a movie at least once a month. How many people were surveyed

scoundrel [369]

Answer:

640 people

Explanation:

480 people = 75 %
x people = 100%

480 : x = 75 : 100
75 x = 48,000
x = 48,000 : 75
x = 640

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3 years ago

Read 2 more answers

The set of all even natural numbers less than 14

lesya [120]

The set of all even numbers less that fourteen would include 2,4,6,8,10,and 12.

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3 years ago

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You have 100 cm of string which can be cut in one place (or not cut at all) and then formed into a circle and a square (or just

Ne4ueva [31]

Answer:

44cm for minimum area and 0 for maximum area (circle)

Step-by-step explanation:

Let's C be the circumference of the circle and S be the circumference of the square. If we cut the string into 2 pieces the total circumferences would be the string length 100cm.

S + C = 100 or S = 100 - C

The side of square is S/4 and radius of the circle is $\frac{C}{2\pi}$

So the area of the square is

$A_S = \frac{S^2}{4^2} = \frac{S^2}{16}$

$A_C = \pi\frac{C^2}{(2\pi)^2} = \frac{C^2}{4\pi}$

Therefore the total area is

$A = A_S + A_C = \frac{S^2}{16} + \frac{C^2}{4\pi}$

We can substitute 100 - C for S

$A = \frac{(100 - C)^2}{16} + \frac{C^2}{4\pi}$

$A = \frac{100^2 - 200C + C^2}{16} + \frac{C^2}{4\pi}$

$A = 625 -12.5C + \frac{C^2}{16} + \frac{C^2}{4\pi}$

$A = 625 -12.5C + C^2(\frac{1}{16} + \frac{1}{4\pi})$

To find the maximum and minimum of this, we can take the first derivative and set that to 0

$A^{'} = -12.5 + 2C(\frac{1}{16} + \frac{1}{4\pi}) = 0$

$C(\frac{1}{8} + \frac{1}{2\pi}) = 12.5$

$C \approx 44 cm$

If we take the 2nd derivative:

$A^{''} = \frac{1}{8} + \frac{1}{2\pi} > 0$

We can see that this is positive, so our cut at 44 cm would yield the minimum area.

The maximum area would be where you not cut anything and use the total string length to use for either square or circle

if C = 100 then $A_C = \frac{C^2}{4\pi} = \frac{100^2}{4\pi} = 795.77 cm^2$

if S = 100 then $A_S = \frac{S^2}{16} = \frac{100^2}{16} = 625 cm^2$

So to yield maximum area, you should not cut at all and use the whole string to form a circle

4 0

3 years ago