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goblinko [34]
3 years ago
5

Many egg producers keep chickens in small cages that do not allow the chickens to move. Some people believe that this is unhealt

hy, so they buy eggs from chickens that are not caged 24-hours a day. These are sometimes called “free-range” chickens. The United States Department of Agriculture (USDA) allows chickens to be called free-range as long as the chickens spend some of their time outside. The European Union (EU), however, has several additional restrictions. One of these is that the farmers must provide enough outside area so that if all the chickens were outside, the density of chickens would be no more than 0.25 chickens/sq meter. (Wikipedia, 2014). Make sure that you fill in each answer area before checking "How Did I Do?". How many square meters does the EU require for one chicken? square meters A farmer in the United States wants to meet the EU guidelines. She measures her area in square yards (1 sq meter =1.196 sq yards). How many square yards does she need for 1,100 chickens? (i) 301.1 square yards (ii) 4,400.0 square yards (iii) 4,812.2 square yards (iv) 5,262.4 square yards
Mathematics
2 answers:
bonufazy [111]3 years ago
6 0

Answer: for 1100 chickens 328.9 sq yards is needed

Step-by-step explanation:

A chicken = 0.25sqm

1sqm =1.196 sq yards

0.836sqm = 1 sq yard

For 1100 chicken

1100*0.25=275sqm

275sqm = 275*1.196

=328.9 sq yards

luda_lava [24]3 years ago
3 0

Answer:

i think the they put them in small cages is to insure a better produce

Step-by-step explanation:

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There are many ways to measure the reading ability of children. Research designed to improve reading performance is dependent on
ELEN [110]

Answer:

A 90% confidence interval to estimate the mean DRP score in Henrico County Schools  is =32±2.7280

i.e. C.I.  [29.3,34.7]

Hence the results are not significant.

Step-by-step explanation:

Given:

Total no of students =44

True mean =32

Standard deviation=11

And all 4 students score also given.

To Find:

90 % confidence interval and conclusion on it.

Solution:

Here for C.I. we required mean, standard deviation and no of students.

So mean =32,S.D.=11 and n=44

Therefore , For 90 % interval Zscore is Z=1.645

C.I.=mean±Z[Standard  deviation/Sqrt(n)]

=32±1.645[11/Sqrt(44)]

=32±1.645[1.6583]

=32±2.7280

i.e. C.I.  [29.3,34.7]

Now Here to commit on calculated interval we should check  value of Z-score

So we need to calculate the sample mean.

Sample mean =Sum of all values /Total no of values.

=[40+ 26 +39+ 14+ 42+ 18 +25+ 43+ 46 +27 +19+ 47+ 19 +26+ 35 +34+ 15+ 44 40+ 38+ 31+ 46 +52 +25+ 35 +35+ 33 +29 +34 +41 +49+ 28+ 42+ 47 +35 +48 +22 33+ 41 +51 +27 +14+ 54 +45]/44

=34.86

Z-score=(sample mean -true mean)/[standard deviation/Sqrt(n)]

=(34.86-32)/[11/Sqrt(44)]

Z=1.72465

For ,

P(Z≥1.72465)=0.08544

For 0.05 significance level  the results are not significant at  p<0.01.

Researcher claimed mean is not correct upto 0.05 significant level

i.e calculated mean and Sample mean are different.

Hence the results are not significant.

6 0
2 years ago
Pls help me 10 points
Dennis_Churaev [7]

Answer:

k=3/5

Step-by-step explanation:

k=y/x

k=3/5

7 0
2 years ago
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d1i1m1o1n [39]
The answer is $8.43 for this question
8 0
3 years ago
How do I solve this equation?
Gnom [1K]

2x(4-x)^{-1/2}-3(4-x)^{1/2}=(4-x)^{-1/2}\bigg(2x-3(4-x)\bigg)

We effectively rewrite the equation as

\dfrac{5x-12}{(4-x)^{1/2}}=0

In order for the LHS to be defined, we need to restrict 4-x>0, or x. Now, the LHS will vanish when the numerator is 0, which happens for

5x-12=0\implies5x=12\implies x=\dfrac{12}5

This value is indeed smaller than 4, so the solution is x=\dfrac{12}5.

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Jason and Marc each bought a new video game for $40.
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Answer:2.50 more dollars then Marc

Step-by-step explanation:

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