Answer:

Step-by-step explanation:
Assuming this complete question:
"Suppose a certain species of fawns between 1 and 5 months old have a body weight that is approximately normally distributed with mean
kilograms and standard deviation
kilograms. Let x be the weight of a fawn in kilograms. Convert the following z interval to a x interval.
"
Previous concepts
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".
Solution to the problem
Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:
Where
and 
And the best way to solve this problem is using the normal standard distribution and the z score given by:

We know that the Z scale and the normal distribution are equivalent since the Z scales is a linear transformation of the normal distribution.
We can convert the corresponding z score for x=42.6 like this:

So then the corresponding z scale would be:

Answer:
x=0
Step-by-step explanation:
Solve for x.
5(x - 3) + 4(x + 3) = 3(x - 1)
Distribute
5x -15 +4x +12 = 3x-3
Combine like terms
9x -3 = 3x-3
Add 3 on each side
9x -3+3 = 3x-3
9x = 3x
Subtract 3x from each side
9x-3x = 3x-3x
6x =0
Divide by 6
6x/6 = 0/6
x=0
Answer:
6
Step-by-step explanation:
base + 2(legs) = 56 (2 legs are the same because it's isosceles)
x + 2(5x - 5) = 56
x + 10x - 10 = 56
11x -10 = 56
11x = 66
x = 6