Answer: 19 cupcakes and 37 cookies were sold.
Step-by-step explanation:
Let x represent the number of cupcakes that Jesse sold yesterday.
Let y represent the number of cookies that Jesse sold yesterday.
If he sold 56 cupcakes and cookies combined, it means that
x + y = 56
Each cupcake sold for $1.50 and each cookie sold for $0.25. At the end of the day, Jesse had sold $37.75 worth of cookies and cupcakes. This means that
1.5x + 0.25y = 37.75 - - - - - - - - - - -1
Substituting x = 56 - y into equation 1, it becomes
1.5(56 - y) + 0.25y = 37.75
84 - 1.5y + 0.25y = 37.75
- 1.5y + 0.25y = 37.75 - 84
- 1.25y = - 46.25
y = - 46.25/ - 1.25
y = 37
x = 56 - y = 56 - 37
x = 19
Answer:
So is there are 10 cats for every 4 dogs,
If there are 5 cats that is half of 10 so half of 4 is 2
Now there are 32 dogs that is 8 times more than 4 so 10 x 4 is 40 so the answers are
Cats 10 5 8
Dogs 4 2 32
Plz give brainiest
Let us name the players A,Dave,Zack,Paul,E and F
For the first position there are two candidades ( Zack / Paul )
For the second position there is only one candidate i.e. Dave
For the third place there will be 4 candidates (out of Zack and Paul - 1 as one of them is already taken for the first position and A, E and F total-4)
For the fourth place there will be 3 candidates ( out of the four available candidates in the 3rd place, one will be taken up for 3rd place )
For the fifth place there will be 2 candidates
Finally, for the last place there will be only one candidate left.
On multiplying the no. of available cadidates, we get 2 * 1 * 4 * 3 * 2 * 1 = 48 i.e. option (A)
Please mention minor spelling mistakes
For the second question:
Let the no of dotted marbles be 'x' and no of striped marbles be 'y'
then the equation will become as follows
(y+6)/x = 3
and
(x+6)/y = (2/3)
On solving the equations, we will get x = 10 and y = 24
Total balls = 10+24+6 = 40 (option E)
Answer 3 will be ) For the first edge, he can choose 3 paths
For the second edge he can choose 2 paths for each path of its first edge's path
For the third , he is bounded to move on the paths created by the first and the second edges hence 1 path for each path created by the first and the second edge together
It will be multiplication of all the possibilities of the paths of the three edges differently.........
i.e. 3 * 2 * 1 = 6
