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3 years ago

Prove your answer as to why 2 m, 2 m, and 4 m will or will not form a triangle.

Mathematics

2 answers:

Elis [28]3 years ago

6 0

Answer:

Because the triangle with the legs 2 and 2 would need to have a third leg less than 4 and greater than 0 and a triangle with side lengths 2 and 4 would need a third side of less than 6 and greater than 2

Step-by-step explanation:

katovenus [111]3 years ago

4 0

Answer:

yes it is

Step-by-step explanation:

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Find the slope of the line passing through the points (7, 8) and (-7, 1). Show your work.

anygoal [31]

Answer:

The slope is $\frac{1}{2}$

Step-by-step explanation:

∵ The rule of the slope passing through 2 points is:

m = $\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

∵ The points are (7 , 8) and (-7 , 1)

∴ m = $\frac{1-8}{-7-7}=\frac{-7}{-14}=\frac{1}{2}$

4 0

3 years ago

Can someone help me with this question?

belka [17]

Option 3 (1/4 x 60) since 59 is close to 60 and 25% can be rewritten as 1/4

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3 years ago

Consider a line whose slope is 6 and which passes through the point (8.–2).

Zolol [24]

Answer:

$y=6(x-8)-2\qquad\text{point-slope form}$

$y=6x-50\qquad\text{slope-intercept form}$

Step-by-step explanation:

The equation of a line can be written in several forms. Two of the most-used forms are the point-slope and the slope-intercept forms.

The point-slope form requires to have one point (xo, yo) through which the line passes and the slope m. The equation expressed in this form is:

$y=m(x-xo)+yo$

The slope-intercept form requires to have the slope m and the y-intercept b, or the y-coordinate of the point where the line crosses the y-axis. The equation is:

$y=mx+b$

The line considered in the question has a slope m=6 and passes through the point (8,-2). These data is enough to find the point-slope form of the line:

$\boxed{y=6(x-8)-2\qquad\text{point-slope form}}$

To find the slope-intercept form, we operate the above equation:

$y=6x-48-2$

$\boxed{y=6x-50\qquad\text{slope-intercept form}}$

3 0

4 years ago

A. AA B. SSS C. SAS D. Not Similar

Ierofanga [76]

The answer is D, not similar.

8 0

3 years ago

Can someone please help with these problems I’m having trouble pls

ololo11 [35]

When the chords intersect inside the circle the sum of the vertical angles and the sum of the referenced arcs are the same. Since the vertical angles are congruent, each is half the sum of the referenced arcs.

Similarly when the chords intersect outside the circle, the angle is half the difference of the arc measures.

It's the same with a tangent; in that case there's just not a part of the arc that's not counted on the side with the tangent.

OK, that's how. Let's try some.

1. x = (88 + 86)/2 = 87

2. x = (150 - 60)/2 = 45

3. The angle is exactly half the subtended arc,

x = 110/2 = 55

4. The referenced arc is 360 - 220 = 140 degrees and x is half, 70.

5. Outside, half the difference, x = (90-20)/2 = 35

6. Angle outside, inner arc 6 degrees, vertical angle is 90 degrees.

90 = (x - 6)/2

180 = x - 6

x = 186

7. There's a special rule for this case but we can treat it as outside, little arc x, big arc 360-x,

60 = (360 - x - x)/2

120 = 360 - 2x

2x = 240

x = 120

8. Inner arc x, outer arc is 360-140-x = 220-x. Half the difference is 38,

38 = (220 - x - x)/2

76 = 220 - 2x

2x = 220 - 76

x = (220 - 76)/2 = 72

9. x is formed by a tangent and a radius, so a right angle, x=90

y is subtended by a 35 degree angle so y=70

10. Remaining triangle angle is 180 - 62 - 28 = 90. Arc that subtends it is double, 180. That means the long side is a diameter.

11. Remaining triangle angle is 180 - 50 - 70 = 60. x=120, y=100, z=140

12. Remaining arc 360 - 170 - 90 = 100. Angles are half.

x=45, y=50, z=85

3 0

3 years ago