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Stella [2.4K]
3 years ago
14

Write the converse of the statement below ⬇

Mathematics
1 answer:
Elan Coil [88]3 years ago
4 0
If the next month is march, then this month is february.
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andreyandreev [35.5K]
The two fours are recurring
6 0
3 years ago
Figure out the slope of the line that passed through each pair of points (4,-11) and (7,-8)​
wlad13 [49]

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slope =  \frac{ - 8 - ( - 11)}{7 - 4}  \\

slope =  \frac{ - 8 + 11}{7 - 4}  \\

slope =  \frac{3}{3}  \\

slope = 1

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

4 0
3 years ago
4x = -36<br> plz helpppp
san4es73 [151]

Hi there! :)

4x=-36

Divide both sides by 4 in order to isolate x:

x=-9

Hope this helps you and have a nice day!

~Just a joyful teen

SilentNature

8 0
2 years ago
PLEASE HELP ME I BEG I WILL GIVE BRAINLIEST
ohaa [14]

Answer:

Mean = (2.2 + 2.4 + 2.5 + 2.5 + 2.6 + 2.7)/6 = 2.48

Standard deviation = √(summation(x - mean)²/n

n = 6

Summation(x - mean)² = (2.2 - 2.48)^2 + (2.4 - 2.48)^2 + (2.5 - 2.48)^2 + (2.5 - 2.48)^2 + (2.6 - 2.48)^2 + (2.7 - 2.48)^2 = 0.1484

Standard deviation = √(0.1484/6

s = 0.16

Standard error = s/√n = 0.16/√6 = 0.065

Part B

Confidence interval is written as sample mean ± margin of error

Margin of error = z × s/√n

Since sample size is small and population standard deviation is unknown, z for 98% confidence level would be the t score from the student t distribution table. Degree of freedom = n - 1 = 6 - 1 = 5

Therefore, z = 3.365

Margin of error = 3.365 × 0.16/√6 = 0.22

Confidence interval is 2.48 ± 0.22

Part C

We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean

For the null hypothesis,

H0: µ = 2.3

For the alternative hypothesis,

H1: µ > 2.3

This is a right tailed test

Since the number of samples is small and no population standard deviation is given, the distribution is a student's t.

Since n = 6

Degrees of freedom, df = n - 1 = 6 - 1 = 5

t = (x - µ)/(s/√n)

Where

x = sample mean = 2.48

µ = population mean = 2.3

s = samples standard deviation = 0.16

t = (2.48 - 2.3)/(0.16/√6) = 2.76

We would determine the p value using the t test calculator. It becomes

p = 0.02

Assuming significance level, alpha = 0.05.

Since alpha, 0.05 > than the p value, 0.02, then we would reject the null hypothesis. Therefore, At a 5% level of significance, the sample data showed significant evidence that the mean absolute refractory period for all mice when subjected to the same treatment increased.

Step-by-step explanation:

7 0
3 years ago
Find the y intercept. I already found the slope is 9.
jeka57 [31]

The slope-intercept form: y = mx + b

We have the slope m = 9, therefore: y = 9x + b.

Next. We have the table:

x | -5 | -2 | 1 | 3 | 4 |

y |-46|-19| 8 |26|35|

(1, 8) → x = 1, y = 8

substitute the values of x and y to the equation:

8 = 9(1) + b

8 = 9 + b |-9

b = -1

Answer: y = 9x - 1 → y-intercept is -1.

8 0
3 years ago
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