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bixtya [17]
3 years ago
15

Plzzzz anyone just LOOK AT THISSSSS do u go to alpha omega academy also if u do could u help me with quiz:1 variable expressions

grade 7 btw plzzzz I'll help u with anything but plzzzz
Mathematics
2 answers:
Gekata [30.6K]3 years ago
6 0
I don’t go to alpha omega academy but could you name some of questions they’re asking to see if I can help at all
Dmitrij [34]3 years ago
5 0

Answer:

no. i dont go to alpha omega academy

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kvasek [131]
<em></em>The\ function\ is\ odd\ if\ f(-x)=-f(x)\\\\We\ know:\\\sin x;\ \tan x\ and\ \cot x\ are\ odds.\\\cos x\ is\ even\ /\cos(-x)=\cos x/\\--------------------\\\\A.\ y=\sec x\\\\\sec(-x)=\dfrac{1}{\cos(-x)}=\dfrac{1}{\cos x}=\sec x-\fbox {NO}\\\\B.\ y=\sin x-\fbox{YES}\\\\C.\ y=\cot x\\\\\cot(-x)=\dfrac{\cos(-x)}{\sin(-x)}=\dfrac{\cos x}{-\sin x}=-\dfrac{\cos x}{\sin x}=-\cot x-\fbox{YES}\\\\D.\ y=\csc x\\\\\csc(-x)=\dfrac{1}{\sin(-x)}=\dfrac{1}{-\sin x}=-\dfrac{1}{\sin x}=-\csc x-\fbox{YES}
6 0
4 years ago
Read 2 more answers
MATLAB Simulation. Develop a Matlab script to simulate the modulation of a 30 kHz carrier with a 0.5 kHz message signal. Use 40%
iren2701 [21]

Answer:

MATLAB code for DSB-SC modulation.

fc=154000; % carrier signal frequency

fm=fc/10; % message signal frequency

fs=100*fc;

t=0:1/fs:4/fm;

xc=cos(2*pi*fc*t);

xm=10*cos(2*pi*fm*t); % amplitude of sinusodial is 10

figure(1)

subplot(2,1,1),plot(t,xc);

title('carrier signal of 154 khz');

xlabel('time (sec)');

ylabel('amplitude');

subplot(2,1,2),plot(t,xm);

title('message signal of 15.4 khz');

xlabel('time (sec)');

ylabel('amplitude');

% DSB-SC MODULATION

z1= xm.*xc;

figure(2)

subplot(2,1,1),plot(t,z1);

title('DSB-SC MODULATION IN TIME DAOMAIN');

xlabel('time (sec)');

ylabel('amplitude');

l1=length(z1);

f=linspace(-fs/2,fs/2,l1);

Z1=fftshift(fft(z1,l1)/l1);

subplot(2,1,2),plot(f,abs(Z1));

title('DSB SC MODULATION IN FREQUENCY DOMAIN');

xlabel('frequency(hz)');

ylabel('amplitude');

axis([-200000 200000 0 3]);

Step-by-step explanation:

6 0
3 years ago
PLS HELP DO NOT JUST PUT A RANDOM ANSWER PLEASE 15 POINTS!!!
sattari [20]

Answer:

Step-by-step explanation:

Where's the question?

But if the question is to represent the equation on the graph then

Just fix in any random value for x,say x=3...then insert into into your equation y=3/2x-1 y=3/2(3)-1 y will be 3.5 when x is 3 so you get a coordinate like(3,3.5) repeat that for about three more values then plot a line

HOPE THIS HELPS

7 0
3 years ago
Someone help me with this will give brainliest
professor190 [17]
It’s 45cm



Step by stem explanation: I did that a few weeks ago and got it right!

Hope it helps! :)
4 0
3 years ago
Math whizzes assemble! this is a tough one, this is a question on my study guide its a screenshot, any help would be appreciated
irga5000 [103]

Answer:

14

Step-by-step explanation:

Knowing the first triangle is isosceles, and given the degree is 69.

We can find the top left angle as 180-69-69=42

42 combine with another angle to make a right angle

90-42=48.

The second triangle is also isosceles, so to find 2

we can use 180-42=138 (supplementary angles rule)

and given 10x-8=138

10x=140

x=14

3 0
3 years ago
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