Answer:
434 sweatshirts were sold
Step-by-step explanation:
$2,170/$5 = 434
ANSWER
Vertical asymptote:
x=1
Horizontal asymptote:
y=1
EXPLANATION
The given rational function is
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


The vertical asymptote occurs at
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
The vertical asymptotes is x=1
The degree of the numerator is the same as the degree of the denominator.
The horizontal asymptote of such rational function is found by expressing the coefficient of the leading term in the numerator over that of the denominator.
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y=1
Answer:
There are 47.12 liters in 12.4 gallons of gasoline.
Option C is correct option.
Step-by-step explanation:
Total Gasoline bought = 12.4 gallons
We are given:
1 gallons = 3.8 liters
So.=, we need to find how many liters in 12.4 gallons of gasoline
1 gallon = 3.8 liters
12.4 gallon = 3.8*12.4
= 47.12 liters
So, there are 47.12 liters in 12.4 gallons of gasoline.
Option C is correct option.
Answer:
can't see anything in this photo because this photo is not clear
Answer:
y = (11x + 13)e^(-4x-4)
Step-by-step explanation:
Given y'' + 8y' + 16 = 0
The auxiliary equation to the differential equation is:
m² + 8m + 16 = 0
Factorizing this, we have
(m + 4)² = 0
m = -4 twice
The complimentary solution is
y_c = (C1 + C2x)e^(-4x)
Using the initial conditions
y(-1) = 2
2 = (C1 -C2) e^4
C1 - C2 = 2e^(-4).................................(1)
y'(-1) = 3
y'_c = -4(C1 + C2x)e^(-4x) + C2e^(-4x)
3 = -4(C1 - C2)e^4 + C2e^4
-4C1 + 5C2 = 3e^(-4)..............................(2)
Solving (1) and (2) simultaneously, we have
From (1)
C1 = 2e^(-4) + C2
Using this in (2)
-4[2e^(-4) + C2] + 5C2 = 3e^(-4)
C2 = 11e^(-4)
C1 = 2e^(-4) + 11e^(-4)
= 13e^(-4)
The general solution is now
y = [13e^(-4) + 11xe^(-4)]e^(-4x)
= (11x + 13)e^(-4x-4)