Answer:
35
Step-by-step explanation:
Answer: INDEPENDENT SAMPLES T-TEST
Step-by-step explanation:
Given that;
sample size n₁ = 40, sample size n₂ = 40
sample mean x₁ = 32.9, sample mean x₂ = 30.6
Standard deviation S₁ = 4.4, Standard deviation S₂ = 5.1
Now
NULL hypothesis H₀ : u₁ = u₂
and Alternative hypothesis H₁ : u₁ > u₂
Therefore based on the information provided above, the type of test that should be used to determine whether the level of nicotine are now lower than what they were 10 years ago is the INDEPENDENT SAMPLES T-TEST
Hi the answer to your question is
((3y - 3.5) / (3y + 6)) * 25.5 = (17
/ 25.5) * 25.5
((3y - 3.5) / (3y + 6)) * 25.5 = 17
(76.5y - 89.25) / (3y + 6) = 17
((76.5y - 89.25) / (3y + 6)) * (3y +
6) = 17 * (3y + 6) 76.5y - 89.25 = 51y + 102 76.5y - 51y = 102 + 89.25
25.5y = 191.25
y = 191.25 / 25.5
<span>y = 7.5</span>
55 is 55% of 100.
percents are based of of 100, so 55 would be 55/100 or 55%.
