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babunello [35]
3 years ago
12

Quadrilateral ABCD ​ is inscribed in a circle.

Mathematics
2 answers:
jeka943 years ago
7 0
2(4x+5)+2(x+15)=360
8x+10+2x+30=360
10x=320
x=32

∠A=4×32+5=133º
Anastaziya [24]3 years ago
5 0

Answer:

133

Step-by-step explanation:

Given is a cyclic quadrilateral ABCD.

We know that in a cyclic quadrilateral, opposite angles are supplementary.

A+C =180

Given that A = 4x+5 and C = x+15

Add these and equate to 180

4x+5+x+15 =1805x=180-20 =160x=32A= 4(32)+5 =133

Verify:

When x= 32, Angle C = 47

A+C = 133+47 = 180

Hence right answer

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Mrs.dean can type 150 words in a minute and a half. Mr.kovacs can type 96 words in 3/4 of a minute prove which teacher can type
slamgirl [31]
Mrs. Dean 150 words per minute, already set up nicely for us
Mr. Kovacs 96 words per 3/4 minute

So we need to adjust 96 words per 3/4 minute to what ever words PER MINUTE.

So, a simple way to do this is change 3/4 to decimal, which would be 0.75 in this case. Knowing that 96 words per 3/4 minute is 25% less than what he would type in a minute, we simply multiple 96 by 1.25 to make up for the 0.25 missing.

Which would get us: Mrs. Dean: 150 wpm
                                 Mr. Kovacs: 96(1.25)=120wpm

Therefore Mrs. Dean types at a greater rate of words per minute, 30 more words per minute to be exact.
3 0
3 years ago
Ginny's piggybank contained $8.80 in quarters, dimes, and nickels. there were two more than five times as many nickels as quarte
SSSSS [86.1K]

Answer:

There are 13 quarters, 67 nickels, and 22 dimes.


Step-by-step explanation:

The value of a quarter is $0.25, the value of dime is $0.10, and the value of a nickel is $0.05. Let there be q quarters, n nickels, and d dimes.

Let's write equations from the statements given:


<u>"Ginny's piggybank contained $8.80 in quarters, dimes, and nickels.":</u>

0.25q+0.1d+0.05n=8.80

<u>"there were two more than five times as many nickels as quarters":</u>

5q+2=n

<u>"4 less than twice as many dimes as quarters":</u>

<u>2q-4=d</u>


Plugging in equation 2 and 3 into equation 1, we can solve for q:

0.25q+0.1(2q-4)+0.05(5q+2)=8.80\\0.25q+0.2q-0.4+0.25q+0.1=8.80\\0.7q=8.80+0.4-0.1\\0.7q=9.1\\q=\frac{9.1}{0.7}=13

<em>Substituting q = 13 into equation 2 will give us nickels:</em>

n=5q+2\\n=5(13)+2\\n=67

<em>Substituting q = 13 into equation 3 will give us dimes:</em>

d=2q-4\\d=2(13)-4\\d=22


There are 13 quarters, 67 nickels, and 22 dimes.

4 0
3 years ago
First person to type supercalifragilisticexpialidocious
brilliants [131]
Supercalifragilosticexpialidocious

good expilnation
5 0
3 years ago
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2.356194 I think that’s what the answer is
3 0
3 years ago
What are the solutions of the equation? x2- 16/25=0
OverLord2011 [107]

x² - 16/25 = 0

x² = 16/25

x = ±√(16/25) = ±4/5

Answer: x=4/5 and x=-4/5

4 0
4 years ago
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