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3 years ago

Find the measure of x.

Mathematics

1 answer:

Valentin [98]3 years ago

5 0

Answer is x= 60
Step by step exploration

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5(x-2) over 3 = -x+2 x=[?]

JulsSmile [24]

Step-by-step explanation:

X = 8/9

X = 8 Over 9

4 0

3 years ago

Read 2 more answers

El productor del números es 28. Sabiendo que el primer número es 3 unidades menor que el segundo, calcula los dos número

Rasek [7]

Answer:

Tienes 3 números, "x", "y", "z"

=> El primero es 20 unidades menor que el segundo:

El primero es "x", y el segundo es "y", entonces:

x = y - 20

=> El tercero es igual a la suma de los dos primeros:

El tercero es "z", entonces:

z = x + y

z = (y - 20) + y

z = 2y - 20

=> Entre los tres suman 120

x + y + z = 120

y - 20 + y + 2y - 20 = 120

4y - 40 = 120

4y = 160

y = 40

Si y = 40, entonces:

x = y - 20

x = 20

Además, z = 2y - 20

z= 60

RPTA:

x=20

y=40

z=60

Step-by-step explanation:

8 0

4 years ago

Negative 10 decreased by 14 times a number

Vilka [71]

-10 - 14x <== ur expression

5 0

3 years ago

Suppose that the population P(t) of a country satisfies the differential equation dP/dt = kP (600 - P) with k constant. Its pop

jeka94

Answer:

The country's population for the year 2030 is 368.8 million.

Step-by-step explanation:

The differential equation is:

$\frac{dP}{dt}=kP(600 - P)\\\frac{dP}{P(600 - P)} =kdt$

Integrate the differential equation to determine the equation of P in terms of t as follows:

$\int\limits {\frac{1}{P(600-P)} } \, dP =k\int\limits {1} \, dt \\(\frac{1}{600} )[(\int\limits {\frac{1}{P} } \, dP) - (\int\limits {\frac{}{600-P} } \, dP)]=k\int\limits {1} \, dt\\\ln P-\ln (600-P)=600kt+C\\\ln (\frac{P}{600-P} )=600kt+C\\\frac{P}{600-P} = Ce^{600kt}$

At t = 0 the value of P is 300 million.

Determine the value of constant C as follows:

$\frac{P}{600-P} = Ce^{600kt}\\\frac{300}{600-300}=Ce^{600\times0\times k}\\\frac{1}{300} =C\times1\\C=\frac{1}{300}$

It is provided that the population growth rate is 1 million per year.

Then for the year 1961, the population is: P (1) = 301

Then $\frac{dP}{dt}=1$ .

Determine k as follows:

$\frac{dP}{dt}=kP(600 - P)\\1=k\times300(600-300)\\k=\frac{1}{90000}$

For the year 2030, P (2030) = P (70).

Determine the value of P (70) as follows:

$\frac{P(70)}{600-P(70)} = \frac{1}{300} e^{\frac{600\times 70}{90000}}\\\frac{P(70)}{600-P(70)} =1.595\\P(70)=957-1.595P(70)\\2.595P(70)=957\\P(70)=368.786$

Thus, the country's population for the year 2030 is 368.8 million.

3 0

4 years ago

Help please 4 x n = -8

larisa [96]

Answer:

-2.

Step-by-step explanation:

4 x -2 = -8.

7 0

3 years ago