Answer:
n=28,m=6
Step-by-step explanation:
Rearrange to give 4704 = m * n^2
Express 4704 in its prime factorisation:
2^5 * 3^1 * 7^2
We know that n must be as large as possible and, because it is squared, be the even numbers.
We get n^2 = 2^4 * 7^2 so n = 2^2*7 = 28
m is the leftovers
2^1*3 = 6
A.
the line that's PR is longer than OR
yes because a is the answer
a = 5
r = -5
n = 9
t_9 = a r^(n - 1)
t_9 = (-1)^n*5 (-5) ^ 8
t_9 = (-1)^9 * 5 * (-5) ^8
t_9 = -1 ( 1953125)
t_9 = - 1953125
(j/3)+5
thats the answer
