Children can be 1/2 Ai or 1/2 Bi
Answer:
A) 0.1 a, 0.9 A
Explanation:
According to the given information, all the individuals in the founder population had free earlobes. Since the allele for the free earlobes (A) is dominant over the one for the attached earlobes (a), the genotype of each of the homozygous dominant founder individual would be "AA". Humans are diploid and one individual has two alleles for each gene in its genome. Total number of alleles for the earlobe in the founder population = 10 x 2 = 20.
Frequency of dominant allele, A in the founder population = total number of homozygous dominant individuals x 2 + the total number of heterozygous genotype / total alleles for the earlobe in the population. There were 8 homozygous dominant and 2 heterozygous dominant individuals in the population.
So, frequency of dominant allele = 8 x 2 + 2 / 20 = 16 + 2 / 20 = 18/20 = 0.9
Since p+q=1; frequency of recessive allele "a" = 1-p = 1-0.9 = 0.1
The correct order of sequence is B-A-C.
Anaphase begins with separation of the duplicated centromeres of each pair of sister chromatids. The daughter chromosomes starts moving toward opposite poles due to the action of the spindle fibres. As this stage chromosomes appear like V or J shape. At the end of anaphase, a complete set of chromosomes has gathered at each pole of the cell.
Answer:
Explanation:
they can not chose to adapt. adaptations occur over a very long period time(darwinism) Evolution is not selective in the sense that the organism being changed can choose.
Answer:
Prokaryotic has no nuculues in their cell, while eukariotic does
Explanation:
eukariotic cells have more than one chromosome, and are also bigger and found in more places.
