Why is (x^2+2xy+y^2) greater than 2(x+y) when x and y are over zero and X>Y
1 answer:
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It is a good idea to get familiar with the operation of your calculator. If you're going to use on-line resources to work problems like this, you can make use of any of several good on-line calculators. Google and Bing search boxes will do calculations for you while observing all the rules of the Order of Operations.
The result of this computation is a number that begins 2.56.... Since the hundredths digit is more than 4, the tenths digit is rounded to the next higher value, from 5 to 6.
Rounded to tenths, 2.1√1.488 = 2.6
we have
<u>The system of equations</u>
-------> equation
-------> equation
Substitute equation in equation
subtract both sides
Divide by both sides
the solution is the point
therefore
the answer is
the solution to the system of equations is the point