Question

Why is (x^2+2xy+y^2) greater than 2(x+y) when x and y are over zero and X>Y

Answer 1

Answer:

Step-by-step explanation:

This is true because if we were to plug in values for x and y the first equation will have a greater value.

Lets try 2 for x and y......

2^2+2(2)(2)+2^2                                                                                              

4+8+4

=16

and for the other expression

2(2+2)

4+4

8

And 16 is greater then 8 this is true for all real rational numbers