Answer:
38feet high
Step-by-step explanation:
Given the following
Length of the string = 40feet (hypotenuse)
Angle of elevation = 71 degrees
Required
Height of the kite (opposite)
Using the SOH CAH TOA identity
Sin theta = opp/hyp
Sin 71 = H/40
H = 40sin 71
H = 40(0.9455)
H = 37.82
Hence the kite is 38feet high (to the nearest whole number)
Answer:
Definitley the second one, trust me.
Step-by-step explanation:
The answer is 2 because the slope is going up which means it’s positive and pick 2 points. And it will be 2/1. 2/1 is the same as 2.
Hello AljakeVillena!

You pull horizontally on a 50-kg crate with a force of 450 n and the friction force on the crate is 250 n. the acceleration of the crate is ?

Given,
- mass of crate = 50 kg
- Force you pull it with = 450 N
- Frictional force = 250 N
- Acceleration = ?
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Let's first find the total force/net force acting on the crate. The total force will be :-
- 450 N - 250 N = <u>2</u><u>0</u><u>0</u><u> </u><u>N.</u>
We subtracted the forces because both the forces act on opposite directions.
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Now, let's find the acceleration of the crate. To find the acceleration we must divide the net force by the mass. So,..
- Acceleration = Force/mass
- a = F/m
- a = 200/50
- <u>a = 4 m/s²</u>
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So, the acceleration of the crate is <u>4</u><u> </u><u>m/</u><u>s²</u><u>.</u>
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Hope it'll help you!
ℓu¢αzz ッ
Answer:
They want you to put it into an expression so that it could be expressed. So, 8 more than n would be 8+n.
Hope This Helps!!! :D