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lianna [129]
3 years ago
6

In an orchard, there are 14 apple trees, 26 orange trees, and a cherry tree. What is the ratio of apple trees to cherry trees?

Mathematics
1 answer:
timofeeve [1]3 years ago
5 0

Answer:

The ratio of apple trees to cherry trees is 14a to 1c

Step-by-step explanation:

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An airplane descends 2.2 miles to an elevation of 8.55 miles. Find the elevation of the plane before its descent.
lutik1710 [3]

Answer:

10.75 miles was the elavation before it's decsecent.

Step-by-step explanation:

Hope this helps! :)

7 0
4 years ago
A car dealership show 216 cars in four months at what rate did the dealership sell cars in
yaroslaw [1]

Answer:

216÷4 = 54

Step-by-step explanation:

3 0
3 years ago
Germany Ron 7 miles per week and increase his distances by 1 mile in each week tell tony runs 3 miles per week and increases his
Lelechka [254]
X represents the amount of weeks:
7+x for Germany and 3+2x for Tony they have to be equal for them to run the same distance:
3+2x=7+x
-3 from each side:
2x=4+x
-x from each side:
x=4
They run the same distance on the fourth week, that distance is 7+4=11

Hope this helps :)
4 0
3 years ago
Louie is trying to find a rectangular canvas for his art project. Its diagonal must measure 23.3 inches and form a 31° angle wit
elena55 [62]
The answer should be 24 inches
6 0
3 years ago
In an investigation of pregnancy-induced hypertension, one group of women with this disorder was treated with low-dose aspirin,
AleksandrR [38]

Answer:

Step-by-step explanation:

Given that in an investigation of pregnancy-induced hypertension, one group of women with this disorder was treated with low-dose aspirin, and a second group was given a placebo. A sample consisting of 50 women who received aspirin has mean arterial blood pressure 120mmHg and standard deviation 10mmHg; a sample of 42 women who were given the placebo has mean blood pressure 115mmHg and standard deviation 12mmHg.

Population variances are equal

H_0: \bar x = \bar y\\H_a: \bar x \neq \bar y

(two tailed test at 5% significance level)

Here x denotes group I and Y group II

                  N       Mean     StDev SE Mean

Sample 1   50     120      10  1.4142

Sample 2 42       115      12  1.8516

Pooled std deviation = 10.9565

df=80

Mean difference= 5

Test statistic t = mean diff/std error = \frac{5}{2.3299}=2.1803

p value = 0.0318

since p <0.05 we reject H0

b) We find p >0.01 hence at 1% significance level we accept H0

This implies that 99% confidence interval contains mean difference =0

4 0
4 years ago
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