Answer:
2. congruent
3. congruent
Step-by-step explanation:
Segments will be congruent if their lengths are the same. Their lengths will be the same if the sum of squares of the x- and y-differences of their endpoint coordinates are the same.
2. B-A = (-4-(-4), 8-1) = (0, 7)
D-C = (5-(-2), -5-(-5)) = (7, 0)
The total of 0² and 7² is the same as the total of 7² and 0², so these segments are congruent. (They are both of length 7.)
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3. B-A = (2-4, 6-1) = (-2, 5)
D-C = (-4-(-2), -3-2) = (-2, -5)
The sum of (-2)² and 5² is the same as the sum of (-2)² and (-5)², so these segments are congruent. (They both are of length √29.)
4016 for 6 months plus 2 month penalty for the annual contract
3690 for month to month contract
Difference 326 less from the month to month
Answer:
Move the decimal so there is one non-zero digit to the left of the decimal point. The number of decimal places you move will be the exponent on the
10. If the decimal is being moved to the right, the exponent will be negative. If the decimal is being moved to the left, the exponent will be positive.
8.185 × 10^9
She tipped the waitress $11.58
Answer:
<em> f ( x ) = - 2x^2 + 3x + 1</em>
Step-by-step explanation:
If f (x ) extends to → − ∞, as x→ − ∞ , provided f(x) → − ∞, as x → +∞, we can rewrite this representation as such;
− ∞ < x < ∞, while y > − ∞
Now the simplest representation of this parabola is f ( x ) = - x^2, provided it is a down - facing parabola;
If we are considering a down - facing parabola, the degree of this trinomial we should create should be even, the LCM being negative. Knowing that we can consider this equation;
<em>Solution; f ( x ) = - 2x^2 + 3x + 1</em>, where the degree is 2, the LCM ⇒ - 2
