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dexar [7]
3 years ago
7

I NEED SERIOUS HELP PLEASE WITH PROBABILITY

Mathematics
2 answers:
Dima020 [189]3 years ago
7 0
1) probability of having a six/ total outcomes
=1/6

2)probability of having a four/ total outcome
=1/6

3) probability of having an even number/total outcome
=3/6= 1/2

4)probability of having a multiple of three/total outcome
=2/6= 1/3
erastova [34]3 years ago
3 0
Since its a six sided die the probability for rolling a single number  ( like six or four) is always going to be 1/6.

and since the dice has the numbers 1, 2, 3, 4, 5 and 6 on it the probability for the even and the odd numbers are the same the even being 2, 4, 6  and odd being 1, 3, 5. the probability is 3/6 or simplified 1/2.
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A bottle of perfume holds 0.55 onice. A bottle of cologne holds p.2 ounce. How many more ounces dose the bottle of perfume hold?
zimovet [89]
It has .33 more ounces if that says .2
7 0
3 years ago
Sarah has 25 candies. Sarah gave 2/5 of the candies to her sister. Of the amount left she gave 2/3 to her friend. How many candi
satela [25.4K]

Answer:

5 candies

Step-by-step explanation:

Total of candy Sarah has = 25candies

If Sarah gave 2/5 of the candies to her sister, the total amount she gave her sister will be 2/5 of 25

2/5 of 25 = 10

The remaining candy left will be 25-10 which is 15.

If she gave 2/3 of amount left to her friend, the amount she gave her friend will be 2/3×15 = 10candies.

The amount of candy Sarah have left will be 15- 10 which is 5candies.

3 0
3 years ago
A.no<br>b.yes<br>the question is in the picture ​
nevsk [136]

B. yes, it's a function

8 0
3 years ago
Help pleaseeeeeeeeeeeeeeeeeeeeeee
bixtya [17]

Answer:  \bold{(1)\ \dfrac{19,683}{64}\qquad (2)\ 16}

<u>Step-by-step explanation:</u>

(1)           (12, 18, 27, ...)

The common ratio is:

r=\dfrac{a_{n+1}}{a_n}\quad r =\dfrac{18}{12}=\boxed{\dfrac{3}{2}}\quad \rightarrow \quad r=\dfrac{27}{18}=\boxed{\dfrac{3}{2}}

The equation is:

a_n=a_o(r)^{n-1}\\\\Given:a_o=12,\  r=\dfrac{3}{2}\\\\\\Equation:\\a_n =12\bigg(\dfrac{3}{2}\bigg)^{n-1}\\\\\\\\9th\ term:\\a_9=12\bigg(\dfrac{3}{2}\bigg)^{9-1}\\\\\\a_9=12\bigg(\dfrac{3}{2}\bigg)^{8}\\\\\\.\quad =\large\boxed{\dfrac{19643}{64}}

(2)\qquad \bigg(\dfrac{1}{16},\dfrac{1}{8},\dfrac{1}{4},\dfrac{1}{2}\bigg)\\\\\\\text{The common ratio is}:\\\\r=\dfrac{a_{n+1}}{a_n}\quad  r=\dfrac{\frac{1}{8}}{\frac{1}{16}}=\boxed{2}\quad \rightarrow \quad r=\dfrac{\frac{1}{4}}{\frac{1}{8}}=\boxed{2}

The equation is:

a_n=a_o(r)^{n-1}\\\\Given:a_o=\dfrac{1}{16},\  r=2\\\\\\Equation:\\a_n =\dfrac{1}{16}(2)^{n-1}\\\\\\\\9th\ term:\\a_9=\dfrac{1}{16}(2)^{9-1}\\\\\\a_9=\dfrac{1}{16}(2)^{8}\\\\\\.\quad =\large\boxed{16}

3 0
3 years ago
5. 6(2+ y)=3(3- y)<br> Help
Maurinko [17]

Answer:

Step-by-step explanation:

4 0
3 years ago
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