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3 years ago

I NEED SERIOUS HELP PLEASE WITH PROBABILITY

2 answers:

7 0

1) probability of having a six/ total outcomes
=1/6

2)probability of having a four/ total outcome
=1/6

3) probability of having an even number/total outcome
=3/6= 1/2

4)probability of having a multiple of three/total outcome
=2/6= 1/3

erastova [34]3 years ago

3 0

Since its a six sided die the probability for rolling a single number ( like six or four) is always going to be 1/6.

and since the dice has the numbers 1, 2, 3, 4, 5 and 6 on it the probability for the even and the odd numbers are the same the even being 2, 4, 6 and odd being 1, 3, 5. the probability is 3/6 or simplified 1/2.

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2 years ago

Read 2 more answers

Diego is solving the equation x^2-12x = 21

uysha [10]

Answer:

The solutions to the quadratic equations will be:

$x=\sqrt{57}+6,\:x=-\sqrt{57}+6$

Step-by-step explanation:

Given the expression

$x^2-12x\:=\:21$

Let us solve the equation by completing the square

$x^2-12x\:=\:21$

Add (-6)² to both sides

$x^2-12x+\left(-6\right)^2=21+\left(-6\right)^2$

simplify

$x^2-12x+\left(-6\right)^2=57$

Apply perfect square formula: (a-b)² = a²-2ab+b²

i.e.

$x^2-12x+\left(-6\right)^2=\left(x-6\right)^2$

so the expression becomes

$\left(x-6\right)^2=57$

$\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}$

solve

$x-6=\sqrt{57}$

add 6 to both sides

$x-6+6=\sqrt{57}+6$

Simplify

$x=\sqrt{57}+6$

also solving

$x-6=-\sqrt{57}$

add 6 to both sides

$x-6+6=-\sqrt{57}+6$

Simplify

$x=-\sqrt{57}+6$

Therefore, the solutions to the quadratic equation will be:

$x=\sqrt{57}+6,\:x=-\sqrt{57}+6$

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Answer:

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Step-by-step explanation:

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gregori [183]

Answer:

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Step-by-step explanation:

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