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2 years ago

How can you add eight 4s together so that the total adds up to 500?

Mathematics

2 answers:

Bess [88]2 years ago

7 0

You can also multiply the 8 4s like 8x4 but it won’t add up to 500

s2008m [1.1K]2 years ago

4 0

Answer:

444+44+4+4+4

Step-by-step explanation:

You might be interested in

What is the answer to -6n^2 - 5n - 7 = -8

soldi70 [24.7K]

Answer:

n = $\frac{1}{3}$ , n = $\frac{1}{2}$

Step-by-step explanation:

6n² - 5n - 7 = - 8 ( add 8 to both sides )

6n² - 5n + 1 = 0 ← in standard form

Consider the product of the factors of the coefficient of the n² term and the constant term which sum to give the coefficient of the n- term

product = 6 × 1 = 6 and sum = - 5

The factors are - 3 and - 2

Use these factors to split the n- term

6n² - 3n - 2n + 1 = 0 ( factor the first/second and third/fourth terms )

3n(2n - 1) - 1(2n - 1) = 0 ← factor out (2n - 1) from each term

(2n - 1)(3n - 1) = 0 ← in factored form

Equate each factor to zero and solve for n

3n - 1 = 0 ⇒ 3n = 1 ⇒ n = $\frac{1}{3}$

2n - 1 = 0 ⇒ 2n = 1 ⇒ n = $\frac{1}{2}$

7 0

2 years ago

he yearbook club had a meeting. The meeting had 24 people, which is three-fourths of the club. How many people are in the club

WINSTONCH [101]

Answer:

32 people

Step-by-step explanation:

If 3/4 equals 24, we need to find the other fourth. We can divided the total number of people by the numerator. 24/8, then add 8, which equals 32.

4 0

3 years ago

student randomly receive 1 of 4 versions(A, B, C, D) of a math test. What is the probability that at least 3 of the 5 student te

alexdok [17]

Answer:

1.2%

Step-by-step explanation:

We are given that the students receive different versions of the math namely A, B, C and D.

So, the probability that a student receives version A = $\frac{1}{4}$ .

Thus, the probability that the student does not receive version A = $1-\frac{1}{4}$ = $\frac{3}{4}$ .

So, the possibilities that at-least 3 out of 5 students receive version A are,

1) 3 receives version A and 2 does not receive version A

2) 4 receives version A and 1 does not receive version A

3) All 5 students receive version A

Then the probability that at-least 3 out of 5 students receive version A is given by,

$\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}\times \frac{3}{4}$ + $\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}$ + $\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}$

= $(\frac{1}{4})^3\times (\frac{3}{4})^2+(\frac{1}{4})^4\times (\frac{3}{4})+(\frac{1}{4})^5$

= $(\frac{1}{4})^3\times (\frac{3}{4})[\frac{3}{4}+\frac{1}{4}+(\frac{1}{4})^2]$

= $(\frac{3}{4^4})[1+\frac{1}{16}]$

= $(\frac{3}{256})[\frac{17}{16}]$

= 0.01171875 × 1.0625

= 0.01245

Thus, the probability that at least 3 out of 5 students receive version A is 0.0124

So, in percent the probability is 0.0124 × 100 = 1.24%

To the nearest tenth, the required probability is 1.2%.

4 0

3 years ago

Which equation can be used to find the volume of the cylinder?

sammy [17]

Answer:

V = 904.32cm3

Step-by-step explanation:

V = r*r*pi*h

= 6*6*3.14*8 = 904.32cm3

7 0

2 years ago

Is 5/6 closer to 1 or 0

Tasya [4]

The easiest way to think about this is to give all of the numbers common denominators:
1 can be written as 6/6
0 can be written as 0/6

Now we can see that 5/6 is only 1/6 away from 1, while it is 5/6 away from 0.

So, 5/6 is closer to 1!

6 0

3 years ago

Read 2 more answers