3 years ago

Angle relationships with parallel lines

Mathematics

1 answer:

bekas [8.4K]3 years ago

7 0

Answer:

<h3>X=180 degree</h3>

<h3>X=77 degree </h3>

<h3>Hope it helps u</h3>

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1) If the perimeter of triangle STU is 125 cm, and segments TW, VW, and VT measure 21 cm, 30 cm, and 24 cm, respectively, what i

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GIVEN: The perimeter of triangle STU is 125.

The segments TW=21 cm

VW=30 cm

VT=24 cm

TO FIND: The length of the segment SU.

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As corresponding sides must be same. so we have,

$\frac{TV}{TS}=\frac{TW}{TU}\\\\ \frac{24}{TS}=\frac{21}{TU}\\\frac{TU}{TS}=\frac{7}{8}=k(say)\\$

Then, TU=7k and TS=8k

$\frac{TV}{TS}=\frac{VW}{SU}\\\\ \frac{24}{TS}=\frac{30}{SU}\\\frac{24}{8k}=\frac{30}{SU}\\SU=10k$

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8·k+7·k+10·k=125

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