(a) Yes all six trig functions exist for this point in quadrant III. The only time you'll run into problems is when either x = 0 or y = 0, due to division by zero errors. For instance, if x = 0, then tan(t) = sin(t)/cos(t) will have cos(t) = 0, as x = cos(t). you cannot have zero in the denominator. Since neither coordinate is zero, we don't have such problems.
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(b) The following functions are positive in quadrant III:
tangent, cotangent
The following functions are negative in quadrant III
cosine, sine, secant, cosecant
A short explanation is that x = cos(t) and y = sin(t). The x and y coordinates are negative in quadrant III, so both sine and cosine are negative. Their reciprocal functions secant and cosecant are negative here as well. Combining sine and cosine to get tan = sin/cos, we see that the negatives cancel which is why tangent is positive here. Cotangent is also positive for similar reasons.
The 21x-8 and the 13x-4 are they angles or are they line segments?
Using the current "regular expressions" in use in Java, Perl, and many other applications, this belongs to "character class" using the [ ] notation.
For characters "either" 1,2,3,4, we write
[1234]
or in this particular case,
[1-4]
Answer: Don't Speak Spanish! SORRY! OR LO SIENTO.
Step-by-step explanation:
Answer:
this line has a slope of 1.
Step-by-step explanation:
you choose two points on the graph that are on the line, then you put the change in y value from one point to the other over the change in x value from one point to another. simplify
