Answer:
Molar mass = 254.60g/mol
Step-by-step explanation:
Mass = 8.02g
Volume = 812mL = 0.812L
Pressure (P) = 0.967atm
Temperature of the gas = 30°C = (30 + 273.15)K = 303.15K
Molecular weight = ?
To solve this question, we'll have to use ideal gas equation, PV = nRT
P = pressure of the gas
V = volume of the gas
n = number of moles of the gas
R = ideal gas constant = 0.082J/mol.K
T = temperature of the gas
PV = nRT
n = PV / RT
n = (0.967 * 0.812) / (0.082 * 303.15)
n = 0.7852 / 24.8583
n = 0.0315 moles
Number of moles = mass / molarmass
Molarmass = mass / number of moles
Molar mass = 8.02 / 0.0315
Molar mass = 254.60g/mol
The molar mass of the gas is 254.60g/mol
X + y = 120000
0.15x - 0.10y = 5500
Multiply both sides of bottom by 100 to remove decimals
x + y = 120000
15x - 10y = 550000
Multiply both sides of top by 10
10x + 10y = 1200000
15x - 10y = 550000
Add the two
25x = 1750000
x = 70000
He paid $70,000 for the property that made a profit, and paid $50,000 for the property that lost value.
Answer:
The answer to the question: "Will Hank have the pool drained in time?" is:
- <u>Yes, Hank will have the pool drained in time</u>.
Step-by-step explanation:
To identify the time Hank needs to drain the pool, we can begin with the time Hank has from 8:00 AM to 2:00 PM in minutes:
- Available time = 6 hours * 60 minutes / 1 hour (we cancel the unit "hour")
- Available time = 360 minutes
Now we know Hank has 360 minutes to drain the pool, we're gonna calculate the volume of the pool with the given measurements and the next equation:
- Volume of the pool = Deep * Long * Wide
- Volume of the pool = 2 m * 10 m * 8 m
- Volume of the pool = 160 m^3
Since the drain rate is in gallons, we must convert the obtained volume to gallons too, we must know that:
Now, we use a rule of three:
If:
- 1 m^3 ⇒ 264.172 gal
- 160 m^3 ⇒ x
And we calculate:
(We cancel the unit "m^3)- x = 42267.52 gal
At last, we must identify how much time take to drain the pool with a volume of 42267.52 gallons if the drain rate is 130 gal/min:
- Time to drain the pool =
(We cancel the unit "gallon") - Time to drain the pool = 325.1347692 minutes
- <u>Time to drain the pool ≅ 326 minutes</u> (I approximate to the next number because I want to assure the pool is drained in that time)
As we know, <u><em>Hank has 360 minutes to drain the pool and how it would be drained in 326 minutes approximately, we know Hank will have the pool drained in time and will have and additional 34 minutes</em></u>.
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Answer:
Step-by-step explanation:
c(t)=40:0≤t≤400
=40+0.50 (t-400):t≥400