the answer is 6/1 and 6/1 simply divide and put the answer over one
Answer:
4 √6
Step-by-step explanation:
We have a few right triangles. We know that a²+b²=c², with c being the side opposite the right angle. Representing the side without a value as z, we have:
m²+z² = (8+4)² = 12²
4²+n²=z²
8²+n²=m²
We have 3 equations with 3 unknown variables, so this should be solvable. One way to find a solution is to put everything in terms of m and go from there. First, we can take n out of the equations entirely, removing one variable. We can do this by solving for it in terms of z and plugging that into the third equation, removing a variable as well as an equation.
4²+n²=z²
subtract 4²=16 from both sides
z²-16 = n²
plug that into the third equation
64 + z² - 16 = m²
48 + z² = m²
subtract 48 from both sides to solve for z²
z² = m² - 48
plug that into the first equation
m² + m² - 48 = 144
2m² - 48 = 144
add 48 to both sides to isolate the m² and its coefficient
192 = 2m²
divide both sides by 2 to isolate the m²
96 = m²
square root both sides to solve for m
√96 = m
we know that 96 = 16 * 6, and 16 = 4², so
m = √96 = √(4²*6) = 4 √6
x² + 5x - 6 can be expressed as (x + 6)(x - 1).
Answer:
x=(y+9)/(1+2w)
Step-by-step explanation:
x-9+2wx=y
We make x the subject
x+2wx=y+9
x(1+2w)=y+9
Divide both sides by (1+2w)
x(1+2w)/(1+2w)=y+9(1+2w)
x=(y+9)/(1+2w)
Let the second no. be x
-3x = 21 → x = 21/-3 → x = -7
