What is max final number if his starting number is 7 2(n + 8 )

[(4096)⁰]⁻⁴ = a)1/(4096)⁴ b)-4 c)4096 d)1

SOVA2 [1]

[(4096)⁰]⁻⁴ = (4096)⁰ = 1

OPTION D

5 0

3 years ago

please help me it is URGENT pls the first one is solve and the 2nd one is simplify I will give u lots of points thank you

klasskru [66]

I.) (5x+3)/4-(2x-4)/3=5
Clear fractions:
3·((5x+3)/4)=15x+9
4·((2x-4)/3)=8x-16
15x+9-(8x-16)=5
15x+9-8x+16=5
Combine like terms:
7x+25=5
7x=-20
x=-20/7

II.) (3/11)·(5/6)-(9/12)·(4/3)+(5/13)·(6/15)
Remember PEMDAS
So first multiply:
3/11·5/6=15/66
9/12·4/3=3/3·1/1=3/3=1
5/13·6/15=1/13·6/3=6/39=2/13
(15/66)-1+(2/13)
Combine:
15/66-1/1=15/66-66/66=-51/66
-51/66+2/3=-51/66+44/66=-7/66
Answer: -7/66 :)

7 0

4 years ago

Read 2 more answers

HELP me please!!!!!!!!

STALIN [3.7K]

Answer:

I think it is letter C.

8 0

3 years ago

Read 2 more answers

Please help me idk this

vichka [17]

Answer:

$\large\boxed{Surface\ Area=63\ cm^2}$

Step-by-step explanation:

We have

square with sides s = 3cm

four triangles with base b = 3cm and height h = 9cm.

The formula of an area of a square:

$A_\square=s^2$

The formula of an area of a triangle:

$A_\triangle=\dfrac{bh}{2}$

Substitute:

$A_\square=3^2=9\ cm^2\\\\A_\triangle=\dfrac{(3)(9)}{2}=\dfrac{27}{2}=13.5\ cm^2$

The Surface Area:

$S.A.=A_\square+4A_\triangle\\\\S.A.=9+4(13.5)=9+54=63\ cm^2$

5 0

3 years ago

Given the information below, write the conclusion in context. 1. H0 : The proportion of defective batteries = 0.02 2. HA : The p

Marizza181 [45]

Answer:

$z = -1.23$

And we can calculate the p value with the following probability taking in count the alternative hypothesis:

$p_v = P(z$

And for this case using a significance level of $\alpha=0.05 ,0.1$ we see that the p value is larger than the significance level so then we can conclude that we FAIL to reject the null hypothesis and we don't have enough evidence to conclude that the true proportion is less than 0.02

Step-by-step explanation:

For this case we want to test the following system of hypothesis:

Null hypothesis: $p =0.02$

Alternative hypothesis: $p < 0.02$

The statistic for this case is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

And for this case we know that the statistic is given by:

$z = -1.23$

And we can calculate the p value with the following probability taking in count the alternative hypothesis:

$p_v = P(z$

And for this case using a significance level of $\alpha=0.05 ,0.1$ we see that the p value is larger than the significance level so then we can conclude that we FAIL to reject the null hypothesis and we don't have enough evidence to conclude that the true proportion is less than 0.02

5 0

3 years ago