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4 years ago

Solve for y. log 5+log y=log 40 enter your answer in the box.

Mathematics

1 answer:

Vadim26 [7]4 years ago

8 0

Answer:

The value of y for given log function is 8 .

Step-by-step explanation:

Given as :

The log function is Log 5 + Log y = Log 40

Or, Log y = Log 40 - Log 5 .........1

∵<u> From the Log property</u>

Log m - Log n = Log $\dfrac{m}{n}$

So, Log 40 - Log 5 = Log $\dfrac{40}{5}$

Or, Log 40 - Log 5 = Log 8 .........2

Now, From eq 1 and 2

Log y = Log 8

∴ y = 8

So, The value of y = 8

Hence, The value of y for given log function is 8 . Answer

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The fraction part of a question with feet and inches

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4 years ago

The object on the right is made from a square-based pyramid joined to a cuboid.

spayn [35]

Answer:

Density of steel = 80.73 gm/ $cm^3$

Step-by-step explanation:

The figure is made up of cuboid and square pyramid.

Height of cuboid, h = 9 cm

Length of cuboid, l = 6 cm

Width of cuboid, w = 6 cm

Volume of cuboid is given by the formula:

$V_{Cuboid} = l \times w \times h$

$V_{Cuboid} = 6 \times 6 \times 9\\\Rightarrow V_{Cuboid} = 324\ cm^3$

Density of Wood , $D_{Cuboid}$ = 0.68g/ $cm^3$

We know that formula of Density is:

$Density = \dfrac{Weight}{Volume}$

$D_{Cuboid} = \dfrac{W_{Cuboid}}{V_{Cuboid}}\\\Rightarrow W_{Cuboid} = V_{Cuboid} \times D_{Cuboid}$

Putting the values:

$W_{Cuboid} = 324 \times 0.68 = 220.32\ gm$

Total weight = $W_{Cuboid} + W_{Pyramid}$

970 = 220.32 $+ W_{Pyramid}$

$W_{Pyramid}$ = 749.68 gm

Volume of pyramid is given as:

$V_{Pyramid}= \dfrac{1}{3} \times \text{Area of Base} \times \text{Vertical Height}$

Base is a square with side 6 cm

$V_{Pyramid}= \dfrac{1}{3} \times 6 \times 6 \times (17 -9)\\V_{Pyramid}= 96\ cm^3$

Density of Steel/Pyramid:

$D_{Pyramid} = \dfrac{W_{Pyramid}}{V_{Pyramid}}\\\Rightarrow D_{Pyramid} = \dfrac{749.68}{96}\\\Rightarrow D_{Pyramid} = 80.73\ gm/cm^3$

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4 years ago

Find the distance between points p (5, 1) and q (3,4)

DENIUS [597]

Answer:

D=3.60

Step-by-step explanation:

$D=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}$

Where

$(x_1,y_1) = (5,1)$

$(x_2,y_2) = (3,4)$

Replacing these values in the distance formula

$D =\sqrt{(5-3)^2+(1-4)^2}$

$D =\sqrt{(2)^2+(-3)^2}$

$D =\sqrt{4+9}$

$D =\sqrt{13}$

$D= 3.60$

4 0

3 years ago

A scale model drawing of a garage is 6 centimeters wide and 9 centimeters long. The scale model uses a scale in which 3 centimet

algol13

The scale factor is 0.6. Then the area of the actual garage is 19.44 m². And dimensions are 3.6 m and 5.4 m.

<h3>What is the scale factor?</h3>

Scale factor means the changing of the size of the object without changing the shape. The size of the object may be increased or decreased based on the scale factor.

Given

A scale model drawing of a garage is 6 centimeters wide and 9 centimeters long.

The scale model uses a scale in which 3 centimeters represent 1.8 meters.

The scale factor will be

$\rm 1 \ cm = 0.6$ m

Then the dimension of the actual garage will be

Length = 0.6 x 6 = 3.6 m

Width = 0.6 x 9 = 5.4 m

Then the area of the actual garage will be

Area of garage = Length x Width

Area of garage = 3.6 x 5.4

Area of garage = 19.44 m²

Thus, the area of the actual garage is 19.44 m². And dimensions are 3.6 m and 5.4 m.

More about the scale factor link is given below.

brainly.com/question/22644306

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3 years ago

Need help on both questions

erastovalidia [21]

Answer:

24, 91

Step-by-step Explanation:

$7) \\ area = 6 \times 4 \\= 24 \: {units}^{2} \\ \\ 8) \\ base \: length = 4 - ( - 9) = 4 + 9 = 13 \\ height \: = 5 - ( - 2) = 5 + 2 = 7 \\ area = base \times height \\= 13 \times 7 = 91 \: {units}^{2}$

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4 years ago

Read 2 more answers