Answer:
#5
x = 45
E
Step-by-step explanation:
Theorems you need:
- The measures of 2 adjacent angles that form a straight line with the outer sides add up to 180°.
- The sum of the interior angles of a triangle add up to 180° ((n-2)×180).
#5
Knowing those, you first want to find the triangle's 3 interior angles.
The angles <QSO & <QSR are adjacent (share a common ray) and form a straight line with the outer rays, therefore they add up to 180.
So m<QSO+m<QSR=180.
Rewrite the equation: m<QSR=180-m<QSO
Plug the known value in: m<QSR=180-(3x-17)
Distribution & Combining like terms: m<QSR=180-3x+17=197-3x
Now solve for the 3 interior angles to equal 180.
(197-3x)+(25)+(2x+3)=180
Combine like terms: 225-x=180
Isolate the x term (-225 to both sides): -x=180-225=-45
Isolate the x (×-1 to both sides):
x=45
We have to factor becasue
area=legnth times width
area=4x^2+28x+49
area=(2x+7)(2x+7)
area=(2x+7)^2
legnth =width
we arent' given area so we can't solve
but, , since it is a squaer room, legnth=width so √area=legnth=width
Answer:
{x,y} = {6/5,23/10}
Step-by-step explanation:
[1] 7x + 2y = 13
[2] 4x + 4y = 14 <---------- linear equations given
Graphic Representation of the Equations : PICTURE
2y + 7x = 13 4y + 4x = 14
Solve by Substitution :
// Solve equation [2] for the variable y
[2] 4y = -4x + 14
[2] y = -x + 7/2
// Plug this in for variable y in equation [1]
[1] 7x + 2•(-x +7/2) = 13
[1] 5x = 6
// Solve equation [1] for the variable x
[1] 5x = 6
[1] x = 6/5
// By now we know this much :
x = 6/5
y = -x+7/2
// Use the x value to solve for y
y = -(6/5)+7/2 = 23/10
// Plug this in for variable y in equation [1]
[1] 7x + 2•(-x +7/2) = 13
[1] 5x = 6
// Solve equation [1] for the variable x
[1] 5x = 6
[1] x = 6/5
// By now we know this much :
x = 6/5
y = -x+7/2
// Use the x value to solve for y
y = -(6/5)+7/2 = 23/10
Answer:
5/9
Step-by-step explanation:
1/3 * 1 2/3
1/3 * 5/3
5/9
The first one since the given measurements/guide is Side, Angle, Side