Is 2.549 the same as2.5

What is the value of the natural logarithm when x=3?

telo118 [61]

Answer:

Step-by-step explanation:

$f(x)=ln(x)\\f(3)=ln(3) = 1.099$

4 0

3 years ago

Read 2 more answers

In a city with a population of 1 million, 500 people have been diagnosed with cancer, whereas the rest of the people do not have

Leni [432]

Class distribution is considered to be normal using normal approximation to binomial.

A frequency distribution is a table that shows classes or intervals of data with a count of the number in each class.

Given :

In a city with a population of 1 million

i.e Population size (N) = 1 million = 1000000

From which 500 people have been diagnosed with cancer

Let X : No. of people have been diagnosed with cancer

X = 500

Population proportion (p) :

p = XNp =5001000000p = 0.0005

So , the proportion of people who do not have cancer (q)=1-p

=1-0.0005

=0.9995

Here the distribution of X is Binomial

Such that :

i. No. of trials are fixed

ii. Probability of success is constant (p=0.0005)

iii. Possible outcomes are two (having cancer or not)

Here we can use normal approximation to Binomial

Because N is very large

So class distribution is considered to be normal using normal approximation to binomial.

To learn more, visit:

brainly.com/question/9325204

#SPJ4

5 0

2 years ago

A spring has a natural length of 7 m. If a 4-N force is required to keep it stretched to a length of 11 m, how much work W is re

bezimeni [28]

Answer:

18 J is the work required to stretch a spring from 7 m to 13 m.

Step-by-step explanation:

The work done is defined to be the product of the force $F$ and the distance $d$ that the object moves:

$W=Fd$

If $F$ is measured in newtons and $d$ <em> </em>in meters, then the unit for is a newton-meter, which is called a joule (J).

This definition work as long as the force is constant, but if the force is variable like in this case, we have that the work done is given by

$W=\int\limits^b_a {f(x)} \, dx$

Hooke’s Law states that the force required to maintain a spring stretched $x$ units beyond its natural length is proportional to

$f(x)=kx$

where $k$ is a positive constant (called the spring constant).

To find how much work W is required to stretch it from 7 m to 13 m you must:

Step 1: Find the spring constant

We know that the spring has a natural length of 7 m and a 4 N force is required to keep it stretched to a length of 11 m. So, applying Hooke’s Law

$4=k(11-7)\\\\\frac{k\left(11-7\right)}{4}=\frac{4}{4}\\\\k=1$

Thus $F=x$

Step 2: Find the the work done in stretching the spring from 7 m to 13 m.

Recall that the natural length is 7 m, so when we stretch the spring from 7 m to 13 m, we are stretching it by 6 m beyond its natural length.

Work needed to stretch it by 6 m beyond its natural length

$W=\int\limits^6_0 {x} \, dx \\\\\mathrm{Apply\:the\:Power\:Rule}:\quad \int x^adx=\frac{x^{a+1}}{a+1},\:\quad \:a\ne -1\\\\\left[\frac{x^{1+1}}{1+1}\right]^6_0\\\\\left[\frac{x^2}{2}\right]^6_0=18$

18 J is the work required to stretch a spring from 7 m to 13 m.

5 0

3 years ago

Example 5 Given m angle7=38^ and m angle10=102^ the measure of each missing angle

kotykmax [81]

angle 1 - 78

angle 2- 102

angle 3- 78

angle 4- 102

angle 5- 38

angle 6- 142

angle 8- 142

angle 9- 78

angle 11- 78

angle 12- 102

angle 13- 38

angle 14- 142

angle 15- 38

angle 16- 142

5 0

3 years ago

Solve 3(x - 2) < 18.

Musya8 [376]

This answer is 290 because when you skip the math you would find the answer

5 0

3 years ago