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Mumz [18]
3 years ago
14

When a stepladder is placed as shown, is it possible for the lower ends of the ladder to be 12 feet apart? Explain​

Mathematics
1 answer:
nataly862011 [7]3 years ago
5 0

Answer:

No, with the guides in between the two ladders, it is not possible for the lower ends of the ladder to be up to 12 feet apart

Step-by-step explanation:

The given parameters are;

The length of two sides of the step ladder = 12 feet

The maximum value allowable for the included angle between the two 12 feet ladders = 58°

Therefore, the maximum value of the third side facing the included angle is given as follows;

let "a" represent the maximum value of the third side formed by the distance apart of the lower end of the ladder, by cosine rule, we have;

a² = 12² + 12² - 2 × 12 × 12 × cos(58°) = 135.383251901

∴ a = √(12² + 12² - 2 × 12 × 12 × cos(58°)) ≈ 11.64

The maximum value of the third side formed by the distance apart of the lower end of the ladder = a ≈ 11.64 feet < 12 feet

Therefore, it is not possible for the lower ends of the ladder to be up to 12 feet apart.

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Answer:

z=\frac{1.83-1.94}{\sqrt{\frac{1.48^2}{180}+\frac{1.62^2}{180}}}}=-0.673  

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Comparing the p value with the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we FAIL to reject the null hypothesis, and a would NOT be a significant difference in the two means

Step-by-step explanation:

Data given and notation

\bar X_{1}=1.83 represent the mean in 1990

\bar X_{2}=1.94 represent the mean for 2005

s_{1}=1.48 represent the sample deviation for 1990

s_{2}=1.62 represent the sample standard deviation for 2005

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n_{2}=180 sample size for 2005

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\alpha=0.05 significance level provided

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We need to conduct a hypothesis in order to check if the means for the two groups are different, the system of hypothesis would be:

Null hypothesis:\mu_{1}=\mu_{2}

Alternative hypothesis:\mu_{1} \neq \mu_{2}

Since we don't know the population deviations for each group, for this case is better apply a t test to compare means, and the statistic is given by:

z=\frac{\bar X_{1}-\bar X_{2}}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}} (1)

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Calculate the value of the test statistic for this hypothesis testing.

Since we have all the values we can replace in formula (1) like this:

z=\frac{1.83-1.94}{\sqrt{\frac{1.48^2}{180}+\frac{1.62^2}{180}}}}=-0.673  

What is the p-value for this hypothesis test?

Since is a bilateral test the p value would be:

p_v =2*P(z

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Comparing the p value with the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we FAIL to reject the null hypothesis, and a would NOT be a significant difference in the two means

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Answer:

1 1/3

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dozen=12

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5 1/3=16/3

16/3 divided by 4/1

KEEP CHANGE FLIP

16/3 times 1/4= 1 1/3

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Answer:

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