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Elan Coil [88]
3 years ago
13

Verify the identity: cos(a+B)/cos a sin B = cot B -tan a

Mathematics
1 answer:
alexgriva [62]3 years ago
5 0
Cos( A + B ) = cosAcosB - sinAsinB ;
cos( A + B ) / ( cosAsinB ) = ( cosAcosB - sinAsinB ) / ( cosAsinB ) = ( cosAcosB ) / ( cosAsinB ) - ( sinAsinB ) / ( cosAsinB ) = cosB / sinB - sinA / cosA = cotB - tanA ;
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What is the sum of the measures of the interior angles of an octagon?
pochemuha
ANY n-sided polygon has interior angles that sum to 180(n - 2) degrees. For an octagon this is 180 x 6 ie 1080 degrees (so the individual interior angles of a regular octagon are 135 degrees).      

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5 0
3 years ago
Read 2 more answers
Answer all questions, your combing like terms. Show ALL of you work! Thank you!!
Elanso [62]

Answer:

1. -12x - 9y - 6

2. -12x + 36

3. -240

4. -2

5. x = -57

6. x = -6

7. x = 48

8. x = 20

9. x = -288

10. n = 8

Step-by-step explanation:

1.

-5x - 13 + 3y - 7x - 12y + 7

-12x - 13 + 3y - 12y +  7

-12x - 6 + 3y - 12y

-12x - 6 - 9y

-12x - 9y - 6

2.

-3(4x - 12)

-3(4x) + (-3)(-12)

-12x + 36

3.

6x - 282

6(7) - 282

42 - 282

-240

4.

6x + 2(y + x)

6(-2) + 2(7 + (-2))

-12 + 2(7 - 2)

-12 + 2(5)

-12 + 10

-2

5.

x - 23 = -80

 + 23    +23

x = -57  

6.

12x = -72

/12     /12

x = -6

7.

x/4 = 12

* 4    * 4

x = 48

8.

3x + 12 = 72

    -  12  - 12

3x = 60

/3     /3

x = 20

9.

x/4 - 8 = -80

     + 8    + 8

x/4 = -72

* 4    * 4

x = -288

10.

-4(1 - 5n) - 8n = 92

-4 + (-4)(-5n) - 8n = 92

-4 + 20n - 8n = 92

-4 + 12n = 92

12n - 4 = 92

     + 4    + 4

12n = 96

/12     /12

n = 8

6 0
3 years ago
*SCIENCE QUESTION* The Prime Meridian runs through:
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The answer is C. Greenwich,England.
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3 years ago
Find the sixth term of the geometric sequence<br> 9, 18, 36, ...
timama [110]

Answer:

This is a geometric sequence because any term divided by the previous term is a constant called the common ratio. r=36/18=18/9=2 A geometric sequence is expressed as

\begin{gathered}a_n=ar^{n-1},\text{ where a=initial term, r=common ratio, n=term number}\\ \\ a_n=9(2^{n-1})\\ \\ a_6=9(2^5)\\ \\ a_6=288\end{gathered}an=arn−1, where a=initial term, r=common ratio, n=term numberan=9(2n−1)a6=9(25)a6=288

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3 years ago
Different groups of 100 graduates of a business school were asked the
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76,000 because it is the outlier
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3 years ago
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