The probability of randomly selecting a yellow marble out of the bag is
Step-by-step explanation:
A bag contains:
- 7 red marbles
- 5 yellow marbles
- 6 blue marbles
- 4 green marbles
- 3 orange marbles
We need to find the probability of randomly selecting a yellow marble out of the bag
Probability is the ratio of number of favorable outcomes to the total number of possible outcomes P(A) =
∵ A bag contains 7 red marbles, 5 yellow marbles, 6 blue
marbles, 4 green marbles, and 3 orange marbles
- Add all the color to find the number of total marbles
∴ n(all) = 7 + 5 + 6 + 4 + 3 = 25
∵ There are 5 yellow marbles
∵ P(yellow) =
∴ P(yellow) =
- Divide up and down by 5 to simplify the fraction
∴ P(yellow) =
The probability of randomly selecting a yellow marble out of the bag is
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Answer:
YR = 33.6 in.
Step-by-step explanation:
△DLZ∼△MYR
LZ / DZ = YR / MR
21/18 = YR / 28.8
7 / 6 = YR / 28.8
YR = 7 * 28.8 / 6
YR = 33.6
<span>Let us start with the schnauzers, the easiest one to imagine. Let us assume that there were x number of schnauzers.
Scottie's are 3 more than schnauzers. So their number is x+3
Wire haired terriers are 5 less than twice the number of schnauzers.
So their number is 2x -5 (2x for twice the number of schnauzers)
Now add all these numbers.
That is x + x+3 + 2x-5 = 4x -2
The total number of dogs, 78, is given in the question
Now we know that 4x -2 =78
4x = 78 +2
= 80
Therefore x = 80/4
= 20.
So there were 20 schnauzers, 23 Scottie’s and 35 wire haired terriers</span>
Let Cedric's age be c
tyshon= 3c-3
3c-3 +c =3c+c-3 = 4c-3
4c-3=57
4c=60
c=15
tyshon=15×3-3 = 42