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ololo11 [35]
3 years ago
6

Line segments AB and CD intersect at point E. Ray EF extends from point E.

Mathematics
1 answer:
Tom [10]3 years ago
7 0

Answer:

x=29 CEF=103 BEF=58

Step-by-step explanation:

161=3x+16+2x

5x=145

x=29

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I mainly need help with part b, brainliest to whoever gets it right
DochEvi [55]

Answer:

y=2x+1

Step-by-step explanation:

8 0
3 years ago
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Three times a larger number is 30 more than 5 times a smaller number. The sum of the larger number and 5 times the smaller numbe
slava [35]
3y  = 5x + 30

y + 5x = 50 .......(1)

3y - 5x = 30 .....(2)        - rearranging the first equation.

Add (1) and (2):-

4y = 80

y = 20  
Now plug y = 20 into equation (1):-
20 + 5x = 50
5x = 30 
x = 6

The 2 numbers are 6 and 20.

5 0
3 years ago
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What is the combined area of the two bases of the following cylinder
Sauron [17]
D. 226.08cm^2

Since we are finding the combined area of the two bases of the cylinder, we are adding the area of the first base with the second base. The formula for the base of a cylinder is pi x r^2, since it is a circle. Since the bases are the same, we can rewrite this as 2pi x r^2.

Since the diameter is 12cm and r = 1/2 diameter, r = 6cm.

Thus, A = 2(3.1415)(6)^2 = 226.08cm^2
4 0
3 years ago
50 PTS ANSWER ALL <3333333
11Alexandr11 [23.1K]

QUESTION 33

The length of the legs of the right triangle are given as,

6 centimeters and 8 centimeters.

The length of the hypotenuse can be found using the Pythagoras Theorem.

{h}^{2}  =  {6}^{2}  +  {8}^{2}

{h}^{2}  = 36+ 64

{h}^{2}  = 100

h =  \sqrt{100}

h = 10cm

Answer: C

QUESTION 34

The triangle has a hypotenuse of length, 55 inches and a leg of 33 inches.

The length of the other leg can be found using the Pythagoras Theorem,

{l}^{2}  +  {33}^{2}  =  {55}^{2}

{l}^{2}  =  {55}^{2}  -  {33}^{2}

{l}^{2}  = 1936

l =  \sqrt{1936}

l = 44cm

Answer:B

QUESTION 35.

We want to find the distance between,

(2,-1) and (-1,3).

Recall the distance formula,

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Substitute the values to get,

d=\sqrt{( - 1-2)^2+(3- - 1)^2}

d=\sqrt{( - 3)^2+(4)^2}

d=\sqrt{9+16}

d=\sqrt{25}

d = 5

Answer: 5 units.

QUESTION 36

We want to find the distance between,

(2,2) and (-3,-3).

We use the distance formula again,

d=\sqrt{( - 3-2)^2+( - 3- 2)^2}

d=\sqrt{( - 5)^2+( - 5)^2}

d=\sqrt{25+25}

d=\sqrt{50}

d=5\sqrt{2}

Answer: D

8 0
3 years ago
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PLEASE HELP..
grin007 [14]
4.56/-2/1/2pi/14/2 is the answer
4 0
3 years ago
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