$(4)\ -6x + y = 11\ \ \ \Rightarrow\ \ \ y=6x+11\\\\(5)\ \ 8x + 2y = 10\ \ \ \Rightarrow\ \ \ 2y=-8x+10\ \ \ \Rightarrow\ \ \ y=-4x+5\\\\(6)\ \ 6x - 3y = -9\ \ \ \Rightarrow\ \ \ -3y=-6x-9\ \ \ \Rightarrow\ \ \ y=2x+3\\\\(7)\ \ -4x + 2y = 16\ \ \ \Rightarrow\ \ \ 2y=4x+16\ \ \ \Rightarrow\ \ \ y=2x+8\\\\
(8)\ \ 10x - 5y = 25\ \ \ \Rightarrow\ \ \ -5y=-10x+25\ \ \ \Rightarrow\ \ \ y=2x-5\\\\(9)\ \ 3x + 2y = -8\ \ \ \Rightarrow\ \ \ 2y=-3x-8\ \ \ \Rightarrow\ \ \ y=-1.5x-4
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6 0

4 years ago

The graph below is a portion of a complete graph. Which graph below is the complete graph assuming it is an even function?

Ierofanga [76]

Answer:

Option b

Step-by-step explanation:

A function is even if and only if f(-x) = f(x).

This means that there is the same value of y for $x_0$ and for $-x_0$

Where $x_0$ is any point belonging to the function .

Therefore you must select a graph whose ordered pairs are of the form $(x_0, y_0)$ and $(-x_0, y_0)$

Therefore the correct answer is option b. Assume that each box in the graph equals 1 unit. Then, for x = 2 y = -3 and for x = -2 y = -3. Then it is shown that the function is even.

8 0

3 years ago

Find the variation constant and an equation of variation where y varies directly as x and y=16 when x=2

Jlenok [28]

Answer:

variation constant = k = 8

equation of variation : y = 8x

Step-by-step explanation:

Any relationship of variation can be written as y = kx

where k is the variation constant.

_______________________________________

Let the equationof relation between y and x be y =kx here as well

given

y = 16 when x = 2

substituting this value in the equation y = kx

16 = k*2

=> k = 16/2 = 8

Thus,

variation constant = k = 8

equation of variation : y = 8x

5 0

3 years ago