Answer:
The answer would be the first one.
m = -3n
Step-by-step explanation:
Answer:
atq= let no.be x and y
x= 4y-3.......(1)
x-2y=7....(2)
subtracting both eqn
x-x+2y=4y-3-7
2y=4y-10
-2y= -10
y=5 ........second no.
first no...x=7+2y=7+10=17.......first no....
Hello,
f(x)=x^3-11x²+40x-48
f(3)=3^3-11*3²+40*3-48=0
f(x)=(x-3)*(x-4)²
Answer D
Answer:
The length of the actual building is 112 meters long.
Step-by-step explanation:
The key words we need to know are these : scale is 1 millimeter = 7 meters, and 16 millimeters long.
The question is asking for the building's actual height.
To solve this, we need to set up a ratio, have the scale being one ratio and the other 16 millimeters over blank. It's going to look like this :
= 
We need to make sure all the units are lined up - the mm parts of the ratio are next to each other.
Now that we have our ratio set up we can cross product to solve for x.
1(x) = 16(7)
x = 112
So x is 112, or the length of the actual building is 112 meters long.
Hope this helps, please mark brainliest if possible. Have a nice day. :)