2 years ago

Can anyone help solve this?

Mathematics

1 answer:

Mashcka [7]2 years ago

5 0

Answer:

12.2

Step-by-step explanation

The triangles are congruent, so the sides are as well. Add 6.1 and 6.1 and you will get 12.2

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What is the equation of the axis of symmetry for this function? H(x) = -X2 + 10x - 11 x = -5 0 x= -10 x = 5 x = 10

siniylev [52]

Given:

The equation of a quadratic function is:

$H(x)=-x^2+10x-11$

To find:

The equation of the axis of symmetry for the given function.

Solution:

If a quadratic function is $f(x)=ax^2+bx+c$ , then the equation of the axis of symmetry is:

$x=-\dfrac{b}{2a}$ ...(i)

We have,

$H(x)=-x^2+10x-11$

Here, $a=-1,b=10,c=-11$ . So, the equation of axis of symmetry by using (i), is

$x=-\dfrac{10}{2(-1)}$

$x=-\dfrac{10}{-2}$

$x=5$

Therefore, the correct option is C.

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