Ask question

Ask question

All categories

3 years ago

13

how do i answer this The school play includes 60 students. 3/5 of the students are actors. The rest of the students work behind

the scenes. a. How many students act in the play? b. How many students work behind the scenes?

1 answer:

artcher [175]3 years ago

8 0

1/5 equals 12 so 12 times 5 is 60 so
a=36
b=24
Your welcome

You might be interested in

Pleaseeeee helpppppp

Bumek [7]

Answer:

Step-by-step explanation:

$\frac{b}{-3}+4< 13$

Step 1: Subtract 4 form both sides

Step 2: Multiply both sides by (-3). when we are multiplying by (-3) the < will change to >.

$\frac{b}{-3}+4-4 9*-3\\\\b > -27$

8 0

2 years ago

Read 2 more answers

5x-7=118 solve for the variable x

myrzilka [38]

X=25 ...... ................

5 0

3 years ago

Read 2 more answers

Can someone plz help with 5, 6 and 7

juin [17]

Answer:

750 people will come in at 15 hours.

Step-by-step explanation:

350 divided by 7=50 50 times 15=750

sorry i don't know the rest

8 0

3 years ago

Read 2 more answers

Geometry Help I can't figure this out and it's stressing me out

stiv31 [10]

Answer:

Reason 3: Definition of sine.

Reason 4: Multiplication property of equality

Reason 6: Division property of equality

5 0

3 years ago

WILL MARK BRAINLIEST!

Artist 52 [7]

Answer:

Following are the responses to the given points:

Step-by-step explanation:

Dilation implies the triangle $\Delta XYZ$ stretched through the factor "2".

$m\angle Y = m\angle C = 90^{\circ} \leftarrow given \\\\$

right triangles:

$\Delta XYZ and \Delta ACB \\\\\angle X \cong \angle A \leftarrow given\\\\$

complementary angles:

$\angle X \ and\ \angle Z$

$m\angle Z = 90^{\circ} - m\angle X \\\\$

complementary angles:

$\angle A \ and\ \angle B$

$m\angle B = 90^{\circ} - m\angle A \\\\\therefore \\\\ \angle Z \cong \angle B \\\\\Delta XYZ \sim \Delta ACB \\\\$

Same triangles: proportional side are corresponding, congruence angles are respective.

$\sin \angle X = \frac{5}{5.59} \leftarrow given \\\\\sin\angle X = \frac{YZ}{XY} \\\\YZ = 5 (units) \rightarrow leg in \Delta XYZ \\\\XZ = 5.59 (units) \rightarrow hypotenuse \ in\ \Delta XYZ\\\\$

Calculating the length of leg XY:

$XY = \sqrt{((5.59)^2 - 52)} \cong 2.4996 (units)\\\\\frac{CB}{YZ} = 2 \leftarrow given \\\\CD = 2YZ = 2 \times 5 = 10 \ (units)\\\\\frac{AC}{XY} = 2 \leftarrow \ given\\\\AC = 2XY \cong 2 \times 2.4996 \cong 4.999\ (units)\\\\$

3 0

2 years ago