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goblinko [34]
3 years ago
12

Solve the system of equations. y=23x–19 x2–y= – 6x–23 Write the coordinates as integers, simplified proper or improper fractions

, or simplified radical expressions.
Mathematics
1 answer:
forsale [732]3 years ago
8 0

Answer:

(3, 50) and (14,303)

Step-by-step explanation:

Given the system of equations;

y=23x–19 ....1

x²–y= – 6x–23 ...2

Substitute 1 into 2;

x²–(23x-19)= – 6x–23

x²–23x+19= – 6x–23 .

x²-23x + 6x + 19 + 23  = 0

x² - 17x + 42 = 0

Factorize;

x² - 14x - 3x + 42 = 0

x(x-14)-3(x-14) = 0

(x-3)(x-14) = 0

x = 3 and 14

If x = 3

y = 23(3) - 19

y = 69-19

y = 50

If x = 14

y = 23(14) - 19

y = 322-19

y = 303

Hence the coordinate solutions are (3, 50) and (14,303)

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Answer:

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Step-by-step explanation:

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(a^4 - 6a^2b^2+ b^4) - (-2a^4+5a^2b^2+ 3b^4)

Solving (a): Simplify

(a^4 - 6a^2b^2+ b^4) - (-2a^4+5a^2b^2+ 3b^4)

Open brackets

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Simplify Like Terms

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