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olga2289 [7]
3 years ago
10

If two fair dice are rolled at the same time, what is the probability that of it obtaining two multiples of 3?

Mathematics
2 answers:
Romashka-Z-Leto [24]3 years ago
6 0
Im assuming this is a non biased 6 sided dice,

multiples of 3 would be 3 and 6 therefore chance of rolling one would be 2/6 = 1/3.

however since the question says two dice at the same time, you have to multiply the probability which would be 1/3 x 1/3 = 1/9

Bingel [31]3 years ago
6 0
How many multiples of three are there in a dice?
6 and 3. So 2.
And there are 6 possible outcomes for each dice, and both dices added there are 12 possible outcomes. This number will be your denominator. 
So since there are 2 in each dice, add them to equal 4, and put the 4 as the nominator. 
Anser: 4/12.
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Thetime(inhours)requiredtorepairamachineis an exponentially distributed random variable with parameter λ = 1 . What is 2 (a) the
mihalych1998 [28]

Answer:

a) 0.1353

b) 0.3679

Step-by-step explanation:

Let's start by defining the random variable T.

T : ''The time (in hours) required to repair a machine''

T ~ exp (λ)

T ~ exp (1)

The probability density function for the exponential distribution is

(In the equation I replaced λ = L)

f(x)=Le^{-Lx}

With L > 0 and x ≥ 0

In this exercise λ = 1 ⇒

f(x)=e^{-x}

For a)

P(T>2)

P(T>2)=1-P(T\leq 2)

P(T>2)=1-\int\limits^2_0 {e^{-x} } \, dx

P(T>2)=1-(-e^{-2}+1)

P(T>2)=e^{-2}=0.1353

For b)

P(T\geq 10/T>9)

The event (T ≥ 10 / T > 9) is equivalent to the event T ≥ 1 so they have the same probability of occur

P(T\geq 10/T>9)=P(T\geq 1)

P(T\geq 1)=1-P(T

P(T\geq 1)=1-(-e^{-1}+1)=e^{-1}=0.3679

4 0
3 years ago
12^13–12^12+12^11 is divisible by 7 and 19.
fiasKO [112]

Answer:

The statement is true

Step-by-step explanation:

The question is as following :

12^{13}-12^{12}+12^{11} is divisible by 7 and 19, true or false?

The given expression is 12^{13}-12^{12}+12^{11}

Take 12^{11} as a common

12^{13}-12^{12}+12^{11} = 12^{11}*(12^2-12^1+12^0)\\= 12^{11} *(144-12+1)\\=12^{11} * 133\\= 12^{11} * 7 * 19

So, 12^{11} * 7 * 19 divided 7 = 12^{11} * 19

And 12^{11} * 7 * 19 divided 19 = 12^{11} * 7

12^{13}-12^{12}+12^{11} is divisible by 7 and 19 (<u>True</u>)

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Please help me out!!!!!
Gnoma [55]
Valid because 3 x 3 is 9 :))
3 0
3 years ago
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Dovator [93]

Answer:

yes

Step-by-step explanation:

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8 0
3 years ago
00.6 times 00.99 how much will you get explain correctly
Helga [31]
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Explanation is the pic
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