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3 years ago

If two fair dice are rolled at the same time, what is the probability that of it obtaining two multiples of 3?

2 answers:

6 0

Im assuming this is a non biased 6 sided dice,

multiples of 3 would be 3 and 6 therefore chance of rolling one would be 2/6 = 1/3.

however since the question says two dice at the same time, you have to multiply the probability which would be 1/3 x 1/3 = 1/9

Bingel [31]3 years ago

6 0

How many multiples of three are there in a dice?
6 and 3. So 2.
And there are 6 possible outcomes for each dice, and both dices added there are 12 possible outcomes. This number will be your denominator.
So since there are 2 in each dice, add them to equal 4, and put the 4 as the nominator.
Anser: 4/12.

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An online store allows sells song downloads for

Nataly [62]

Answer:

[25/1.50]

Step-by-step explanation:

$25 divided by $1.50 and you get 16.667 but we cannot buy another song download with .667 so the answer would by 16 and we write that as [25/1.50]

with the brackets.

So, the answer is B. [25/1.50]

5 0

3 years ago

Read 2 more answers

I just need help cause if I don’t I don’t know what imma do

erica [24]

Answer:

$P(32) = \frac{1}{90}$

$P(Odd) = \frac{1}{2}$

$P(Multiples\ 5) = \frac{1}{5}$

Step-by-step explanation:

Given

Sample Space = 10 to 99

First, we calculate the sample size (n)

$n = 99 - 10 + 1$

$n = 90$

Solving (a): P(32)

In 10 to 99, there is only 1 32.

So,

$P(32) = \frac{n(32)}{n}$

$P(32) = \frac{1}{90}$

Solving (b): P(Odd)

There are 45 odd numbers between 10 and 99

i.e.

$n(Odd) = 45$

So:

$P(Odd) = \frac{n(Odd)}{n}$

$P(Odd) = \frac{45}{90}$

$P(Odd) = \frac{1}{2}$

Solving (c): P(Multiple of 5)

There are 18 multiples of 5 between 10 and 99

i.e

$P(Multiples\ 5) = \frac{18}{90}$

$P(Multiples\ 5) = \frac{1}{5}$

4 0

3 years ago

Can someone please help me with these two questions, because I really don't understand them.

polet [3.4K]

~Hello There!~

19. You can use Pythagoras to figure out the missing length of the triangle
√15² - 9² = 12
(12 x 9)/2 = 54
((20 + 32) / 2) x 9 = 234
234 + 54 = 288

That's what i got ^^ Not 100% sure if its correct

20. 8 + 3 + 6 + 3 = 20
20/4 = 5
Mean = 5

Hope This Helps You!
Good Luck :)
Have A Great Day ^_^

- Hannah ❤

7 0

4 years ago

The kite shown has a width of 24 inches and a total height of 42 inches. What is the total area of the kite without the tail? Sh

joja [24]

Answer:

504 in²

Step-by-step explanation:

The area of a kite is given by :

(a * b) / 2

Where a and b are the width and height of the kite :

Width = 24 inches ; height = 42 inches

Hence,

Area of kite = (24 * 42) / 2

Area of kite = 24 * 21

Area of kite = 504 in²

3 0

3 years ago

Find the value of the expression 74.9+5.23-81.4-16

stich3 [128]

Answer:

To find the value of this expression you need to add and subtract from left to right

74.9+5.23-81.4-16 (add the first two, first)

80.13-81.4-16 (74.9+5.23=80.13) (next subtract the next two)

-1.27-16 (80.13-81.4=-1.27) (Last subtract the last two)

-17.27 (-1.27-16=-17.27)

-17.27

Hope this helps ;)

3 0

3 years ago